Answer:
1. volume = L
2. length = m
3. area = m²
4. mass = kg
5. weight = lbs
6. density = g/cm³
Step-by-step explanation:
i learned this stuff
If you know the slope of a linear relationship as well as one of the points, you can determine if the relationship is proportional if the value of y is equal to the value of the slope times the x value.
<h3>When is a relationship proportional?</h3>
The linear relationship of x and y is said to be proportional if:
y = slope × x
This means that the value of y is directly related to the value of x such that when x is increased by a certain value, you get y.
If this condition is not satisfied then the relationship is not proportional.
The linear relationship above is therefore proportional if the value of y in the point is the same as x when multiplied by the slope.
Find out more on proportional relationships at brainly.com/question/3383226
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First, recall that the equation of a line is
y = mx+b
where
m = slope
b = y-int
The key to this question is the details :
Horizontal line ---> This tells you that your slope is 0
y-int = 3.5 -----> In the equation above, b=3.5
Therefore,
y = 0x + 3.5
y = 0 + 3.5
y = 3.5
Answer:

Step-by-step explanation:
Start by making the denominators of both fraction the same. This can be done by multiplying one fraction's denominator by the other.
After simplifying and combining the two fractions together, check if the numerator can be factorised such that there is a common factor in the denominator and numerator. In this case, the numerator cannot be factorised.
Lastly, expand the denominator.







- Given - <u>a </u><u>rectangle </u><u>with </u><u>length</u><u> </u><u>2</u><u>5</u><u> </u><u>feet </u><u>and </u><u>perimeter </u><u>8</u><u>0</u><u> </u><u>feet</u>
- To calculate - <u>width </u><u>of </u><u>the </u><u>rectangle</u>
We know that ,

where <u>b </u><u>=</u><u> </u><u>width </u><u>/</u><u> </u><u>breadth</u> of rectangle
<u>substituting</u><u> </u><u>the </u><u>values </u><u>in </u><u>the </u><u>formula </u><u>stated </u><u>above </u><u>,</u>

hope helpful ~