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AlexFokin [52]
3 years ago
6

List one way a parallelogram and a rhombus are different

Mathematics
2 answers:
serious [3.7K]3 years ago
4 0
The rhombus has equal side lengths while the parallelogram doesn't have equal side lengths.
Ganezh [65]3 years ago
4 0
A parallelogram every side across from it is paralle and a rhoumbus dosen't have matching sides 
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What is the exact value of the exponential equation, 4(10)5x=200 ?
Rasek [7]

Answer:

4(10)5x=200 = x=log50 / 5

Step-by-step explanation:


7 0
4 years ago
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Find the volume of a pyramid with a square base, where the side length of the base is
ValentinkaMS [17]

Answer:

<h2>1529.4 m³</h2>

Step-by-step explanation:

Volume of a pyramid can be found by using the formula

v =  \frac{1}{3}  \times a \times h \\

a is the area of the base

h is the height

Since the base is a square we have

v =  \frac{1}{3}  \times  {15.3}^{2}  \times 19.6 \\  = 78.03 \times 19.6 \\  = 1529.388

We have the final answer as

<h3>1529.4 m³</h3>

Hope this helps you

3 0
3 years ago
What are 5 words that contain the greek or Latin root/affix
blagie [28]
<span>ambi  for ambiguous.
aqua  for aquarium.
cent  for century.

bio for biology.
homo for homonym.

Hope this helps !

Photon</span>
5 0
3 years ago
Read 2 more answers
suppose you create a graph of the cost function, c=20n + 500 of a new bookstore, and you also graph the revenue function, r=25n,
sdas [7]

Answer:

Loss section

Step-by-step explanation:

Given

c = 20n + 500 -- cost

r = 25n -- revenue

Required

Determine where n = 150 is

To do this, we substitute 150 for n in the given functions

c = 20n + 500

c = 20 * 150 + 500

c = 3500

r = 25n

r = 25 * 150

r = 3750

The above shows that the revenue is greater than cost for n = 150.

This implies that, n = 15o is the loss section.

6 0
3 years ago
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If triangle ABC is similar to triangle DEC, find the values of x and y.
Mumz [18]

The values are x=8 and y=35, if the given ΔABC and ΔDEC are equal, it is obtained by Pythagoras theorem.

Step-by-step explanation:

The given are,

           From ΔABC,

                    AB= 6

                    BC= 10

                    AC = x

           From ΔDEC,

                    CD= 28

                    DE= 21

                    CE = y

Step:1

        Pythagoras theorem from  ΔABC,

                    BC^{2}=AB^{2} + AC^{2}...............(1)

       Substitute the values,

                   10^{2} = 6^{2} + AC^{2}

                  100 = 36 + AC^{2}

                   AC^{2} = 100 - 36

                           = 64

                    AC = \sqrt{64}

                    AC = 8

                  AC = x = 8

Step:2

        Pythagoras theorem for ΔDEC,

               CE^{2} = CD^{2}  + DE^{2}................(2)

       From the values,

              CE^{2} = 28^{2} + 21^{2}

             CE^{2} = 784 + 441

                     = 1225

              CE = \sqrt{1225}

              CE = 35

             CE = y = 35

Result:

         The values are x=8 and y=35, if the given ΔABC and ΔDEC are equal.

5 0
3 years ago
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