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3 years ago

To play the lottery in a certain state a person has to correctly select 5 out of 45 numbers

Mathematics

1 answer:

nika2105 [10]3 years ago

5 0

is that a true or false kind of question or what is it meant to be?

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A card is Chosen at random from a deck of 52 cards it is replaced and a second card is chosen what is the probability both cards

ankoles [38]

There are 4 aces in a deck of 52 cards. the odds of drawing one is 1/13. the probability of doing it again is still 1/13. the odds of doing it twice, as described, is then 1/13 * 1/13, or (1/13)², or 1/169 option A

6 0

4 years ago

Read 2 more answers

53x52 step by step plzzz

Zigmanuir [339]

Answer: here you go i tried my best

Step-by-step explanation:

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3 years ago

12. Find m?1 if m?2 = 35° in parallelogram ABCD. A. 55° B. 35° C. 75° D. 40°

brilliants [131]

Answer: A

Step-by-step explanation: Complementary angles must add up to 90 degrees.

8 0

3 years ago

Determine whether The given segments have the same length. Justify your answer

Semenov [28]

We know the distance formula is

$\sqrt{ (x_{2}-x_{1})^2+ (y_{2}-y_{1})^2 }$

Here A( -4,2) and B(1,4)

So length of AB

= $\sqrt{(1-(-4))^2+(4-2)^2} =\sqrt{5^2+2^2} =\sqrt{29}$

Also C(2,1)

Length of BC

= $\sqrt{(2-1)^2+(-1-4)^2} =\sqrt{1^2+(-5)^2} =\sqrt{26}$

So we can see that length of AB is not equal to length of BC

11.

Now AB = $\sqrt{29}$

Also C(2,-1) & D(4,4)

Length of CD

= $\sqrt{(4-2)^2+(4-(-1)) ^2} =\sqrt{2^2+5^2} =\sqrt{29}$

Yes AB = CD

5 0

3 years ago

A circle is centered at the point (-7, -1) and passes through the point (8, 7).

Sergeu [11.5K]

we know the circle's center is at -7, -1, and we know the circle itself passes through 8,7, the distance from the center to a point on it is by definition its radius, therefore

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\\stackrel{center}{(\stackrel{x_1}{-7}~,~\stackrel{y_1}{-1})}\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{7})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}\\\\\\\stackrel{radius}{r}=\sqrt{[8-(-7)]^2+[7-(-1)]^2}\implies r=\sqrt{(8+7)^2+(7+1)^2}\\\\\\r=\sqrt{15^2+8^2}\implies r=\sqrt{225+64}\implies \boxed{r=17}$

and since we know that x = -15 for such a point, then

$\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2\qquad center~~(\stackrel{-7}{ h},\stackrel{-1}{ k})\qquad \qquad radius=\stackrel{17}{ r}\\\\\\\[x-(-7)]^2+[y-(-1)]^2=17^2\implies (x+7)^2+(y+1)^2=289\\\\\\\stackrel{\textit{since we know x = -15}}{(-15+7)^2+(y+1)^2=289}\implies (-8)^2+\stackrel{FOIL}{(y^2+2y+1^2)}=289\\\\\\64+y^2+2y+1=289\implies y^2+2y=224\implies y^2+2y-224=0\\\\\\(y+16)(y-14)=0\implies y=\begin{cases}-16\\14\end{cases}$

since it's a circle, it touches x = -15 twice, check the picture below.

6 0

3 years ago