The required zero places of the given equation y= x² + 5x + 6 is x = -2 and x = -3.
Given that,
An equation y= x² + 5x + 6,
To determine the Zeros of the equation given above.
<h3>What is the equation?</h3>
The equation is the relationship between variables and is represented as y =ax + b is an example of a polynomial equation.
Here, given equation is, y= x² + 5x + 6
Now, let y = 0
x² + 5x + 6 = 0
x² + 2x + 3x + 6 = 0
x(x + 2) + 3 (x + 2) = 0
(x + 2) * (x + 3) = 0
x + 2 = 0 ; x + 3 = 0
x = -2 and x = -3
Thus, the required zero places of the given equation y= x² + 5x + 6 is x = -2 and x = -3.
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First we have to multiply the numerator and the denominator by 5:
=
0.35
Four hundred eighty-five thousand eight hundred thirty
Area= height x length
= (3x+5)²
= 9x²+30x+25
Perimeter= All sides added together
= 4 (3x+5)
= 12x + 20
Hope this helps!
Answer:
y=17/3x+2
Step-by-step explanation:
Get 2 points from the graph
(3;19) (-10;2)
Grad=change in y/change in x
=2-19/-10-3
=-17/-13
=17/3
y=mx+c
19=17/13(3)+c
19=17+c
19-17=c
2=c
y=17/13x+2.
Well I think you are supposed to find the equation of the line so I think that's it.
