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babymother [125]
4 years ago
6

2. Joseph needs to place chairs in equal rows.

Mathematics
1 answer:
masha68 [24]4 years ago
8 0

Answer: 5 rows, 11 chairs in each row

Step-by-step explanation:

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A manufacturing company uses two different machines, A and B, each of which produces a certain item part. The number of defectiv
damaskus [11]

Answer:A-The mean is 0 and the distribution is approximately normal.

Step-by-step explanation:

8 0
3 years ago
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Someone help please please someone
aev [14]

(1-52/2+5)=(1-26+5)=(-25+5)=-20

continuing:

-20*2*6*6= -40*6*6=-240*6=-1440

result: -1440

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3 years ago
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Evaluate 17p - 2, when p = 1
Bad White [126]

Answer:

It's 15

Step-by-step explanation:

17(1)=17

17-2=15

8 0
3 years ago
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A particular electronic component is produced at two plants for an electronics manufacturer. Plant A produces 70% of the compone
Vesna [10]

Answer:

If a component received by the manufacturer is defective, the probability that it was produced at plant A is 0.5385 = 53.85%.

Step-by-step explanation:

We use the Bayes Theorem to solve this question.

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Defective component

Event B: Produced at plant A.

Plant A produces 70% of the components used

This means that P(B) = 0.7

Among the components produced at plant A, the proportion of defective components is 1%.

This means that P(A|B) = 0.01

Probability of a defective component:

1% of 70%(defective at plant A)

2% of 100 - 70 = 30%(defective at plant B). So

P(A) = 0.01*0.7 + 0.02*0.3 = 0.013

If a component received by the manufacturer is defective, the probability that it was produced at plant A is

P(B|A) = \frac{0.7*0.01}{0.013} = 0.5385

If a component received by the manufacturer is defective, the probability that it was produced at plant A is 0.5385 = 53.85%.

4 0
3 years ago
This year, students in the 9th grade are collecting dimes and quarters for a school fundraiser. They are trying to collect more
BabaBlast [244]

Answer:

0.10d + 0.25q > 143.88

Step-by-step explanation:

Let the total dimes collected be d.

1\ dime = \$0.10

d\ dimes = \$0.10d

Let the total quarters collected be q.

1\ quarter = \$0.25

q\ quarters = \$0.25q

Last\ Year = \$143.88

Required

Represent as an inequality

The total collection, this year, can be represented as:

Total = 0.10d + 0.25q

From the question, we understand that:

This year's collections is expected to be greater than last year's

This can be represented as:

Total > Last\ Year

Substitute in the right values:

0.10d + 0.25q > 143.88

4 0
3 years ago
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