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saul85 [17]
3 years ago
15

Given right triangle A w/a hypotenuse length of 3y + x and a leg of y-x, and right triangle B, w/ a hypotense length of y+5 and

a leg length of x+5, for what values of x and y are the triangles congruent by HL?
Mathematics
1 answer:
Darya [45]3 years ago
4 0
We use the law of correspondence that is 
Hypotenuse = Hypotenuse Leg = Leg 

3y + x = y + 5 
and 
y - x = x + 5 --------------------------------- work on your first problem to find x 
x = -2y + 5 
now you can plug this in to your second equation to sub in for the x 
y - ( -2y + 5 ) = ( -2y + 5 ) + 5 y + 2y - 5 = -2y + 10 3y - 5 = -2y + 10 5y = 15 y = 3 
Now you can plug back in to solve for x 

3y + x = y + 5 3(3) + x = (3) + 5 9 + x = 8 x = -1 
so y = 3 and x = -1
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Answer:

v=\sqrt{\frac{3gh}{2}}

Step-by-step explanation:

If air resistance is neglected, the energy is constant. That means that in every point in the trajectory the energy is the same.

At the point of height h, all the energy is potential and velocity is zero (no kinetic energy)

E=mgh

At point of height h/4, some of the potential energy has transformed in kinetic energy and the velocity is no longer zero. But we know the total amount of energy is the same as the maximum height point.

With that information, we can calculate the velocity v:

E=mg(\frac{h}{4})+m\frac{v^2}{2}=mgh\\\\m\frac{v^2}{2}=mg(h-\frac{h}{4})\\\\\frac{v^2}{2}=\frac{3gh}{4}\\\\v^2=\frac{3gh}{2}\\\\v=\sqrt{\frac{3gh}{2}}

7 0
4 years ago
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Given: rectangle ABCD is similar to rectangle ZBXY. If ZY = 5, XC = 3, DC = 4, then XY =
soldier1979 [14.2K]

Answer:

The length of XY is either 10 or 2.5.

Step-by-step explanation:

Given information: ZY = 5, XC = 3 and DC = 4.

Case 1: Rectangle ABCD is smaller than ZBXY.

The opposite sides of the rectangle are same.

ZY=BC+XC

5=BC+3

2=BC

The length of ABCD is 4 and width of ABCD is 2. The width of ZBXY is 5. The corresponding sides of the similar rectangles are is in the same proportion.

\frac{4}{XY}=\frac{2}{5}

\frac{4\times 5}{2}=XY

10=XY

Therefore the value of XY is 10.

Case 2: Rectangle ABCD is larger than ZBXY.

ZY=BC-XC

5=BC-3

8=BC

The length of ABCD is 4 and width of ABCD is 8. The width of ZBXY is 5. The corresponding sides of the similar rectangles are is in the same proportion.

\frac{4}{XY}=\frac{8}{5}

\frac{4\times 5}{8}=XY

2.5=XY

Therefore the value of XY is 2.5.

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3 years ago
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Answer:

K(3,1),And K(1,-5),j(0,2) t

Step-by-step explanation:


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3 years ago
2x + 3y = 17<br> 5x + 6y = 32<br><br> Usibg method if elimination
lions [1.4K]

Answer:

Solution (-2, 7)

Step-by-step explanation:

2x + 3y = 17      (1)

5x + 6y = 32    (2)

Using elimination method

Multiply (-2) to the equation (1)

-4x - 6y = -34  

Now you have 2 new equations

-4x - 6y = -34

5x + 6y = 32

----------------------------Add

x = -2

Substitute x = -2 into 2x + 3y = 17

2(-2) + 3y = 17

- 4 + 3y = 17

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Solution (-2, 7)

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8 times of the eight term of an arithmetic progression is equal to 12 times of the twelfth term. find its first term if the comm
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Answer:

a₁ = 38

Step-by-step explanation:

Given AP, where:

  • 8a₈ = 12a₁₂
  • d = -2,
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=============

<h3>Solution</h3>

aₙ = a₁ + (n-1)d

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8a₈ = 12a₁₂

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3 years ago
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