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4 years ago

The circamference for a circle that has a radius or 7 inches is

Mathematics

1 answer:

Art [367]4 years ago

8 0

C = π×2×7
c=π×14
c=43.98229715in
c=44in

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What is the area of a semicircle whose perimeter is 72cm

Nuetrik [128]

Answer:

A = 307.9 sq/cm

Step-by-step explanation:

Find the radius of the semi-circle

diameter + half the circumference = 72 cm

2r + pi*r = 72

r(2+pi) = 72

r = 72%2F%28%282%2Bpi%29%29

r = 14

what will be the area of that semicircle?

A =1%2F2*pi%2A14%5E2

A = 307.9 sq/cm

7 0

4 years ago

I have a goal of getting exactly $100. But I have to pay a tax of 10%. How much money do I need to get in order to have exactly

frosja888 [35]

<h3>Answer: $111.11</h3>

=======================================================

Explanation:

Let's say you earn x dollars.

You pay 10% tax on that, which means you pay 0.10x dollars.

This would drop to x-0.10x = 0.90x which is the amount earned after tax.

So you pay 10% of what you earn, and keep 90% of the rest.

Set this equal to the target $100 you want and solve for x.

0.90x = 100

x = 100/0.90

x = 111.11

Notice that 10% of this is 0.10*x = 0.10*111.11 = 1.11 when rounding to the nearest penny. So you'll pay $1.11 in tax. Therefore, you'd have x-0.10x = 111.11 - 1.11 = 100 left over. So the answer checks out.

7 0

3 years ago

Jenny is running for president of the chess club, and she received 36 votes. There are 50 members in the club. What percentage o

grandymaker [24]

Answer:

$72\%$

Step-by-step explanation:

$\frac{36}{50}=\frac{72}{100}=0.72=72\%$

8 0

2 years ago

Read 2 more answers

The marketing club at school is opening a student store. They randomly survey 50 students about how much money they spend on lun

Luden [163]

Answer:

The expected value for a student to spend on lunch each day = $5.18

Step-by-step explanation:

Given the data:

Number of students______$ spent

2 students______________$10

1 student________________$8

12 students______________$6

23 students______________$5

8 students_______________$4

4 students_______________$3

Sample size, n = 50.

Let's first find the value on each amount spent with the formula:

$\frac{num. of students}{sample size} * dollar spent$

Therefore,

For $10:

$\frac{2}{50} * 10 = 0.4$

For $8:

$\frac{1}{50} * 8 = 0.16$ l

For $6:

$\frac{12}{50} * 6 = 1.44$

For $5:

$\frac{23}{50} * 5 = 2.3$

For $4:

$\frac{8}{50} * 4 = 0.64$

For $3:

$\frac{4}{50} * 3 = 0.24$

To find the expected value a student spends on lunch each day, let's add all the values together.

Expected value =

$0.4 + $0.16 + 1.44 +$2.3 + $0.64 + $0.24

= $5.18

Therefore, the expected value for a student to spend on lunch each day is $5.18

7 0

3 years ago

PLEASE PLEASE PLEASE HELP!

Virty [35]

I think the answer may be 2.1 I'm not 100 percent sure

5 0

4 years ago

Read 2 more answers