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ad-work [718]
4 years ago
9

What is the area of a semicircle whose perimeter is 72cm

Mathematics
1 answer:
Nuetrik [128]4 years ago
7 0

Answer:

A = 307.9 sq/cm

Step-by-step explanation:

Find the radius of the semi-circle

diameter + half the circumference = 72 cm

2r + pi*r = 72

r(2+pi) = 72

 

r = 72%2F%28%282%2Bpi%29%29

r = 14

:

what will be the area of that semicircle?

A =1%2F2*pi%2A14%5E2

A = 307.9 sq/cm

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y=MX+c

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y=3/2x-7/2

so slope is.. m=3/2

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A palm tree casts a shadow that is 28 feet long. A 6-foot sign casts a shadow 8 feet long.
s2008m [1.1K]

Answer: The height of the palm tree is 21 feet.

Step-by-step explanation:

We can use a ratio to solve this:

Actual height to shadow for both objects. The fraction equivalents must be equal.

6/8 = x/28 . Cross multiply

6(28) = 8x

168 = 8x   Divide both sides by 8  (8's "cancel" on the right)

168/8 =8x/8

21 = x . This gives us the tree's height as 21 feet.

<em>Another way to solve this is to use the ratios, but simplify the first fraction</em>

<em>6/8 = 3/4</em>

<em>Then multiply the length of the shadow by 3/4</em>

<em>3/4 × 28 = height</em>

<em>28÷4 = 7    7 × 3 = 21</em>

<em>21  feet= the height of the palm tree.</em>

3 0
3 years ago
A computer purchased for $1,650 loses 19% of its value every year.
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Jacob walks 1.5 miles north. He turns and walks 0.8 miles west. How far is he from his starting point?
Flura [38]

Answer:

1.7 miles

Step-by-step explanation:

Given that,

Jacob walks 1.5 miles north.

He turns and walks 0.8 miles west.

We need to find how far is he from his starting point. Let he is at a distance of x miles from the starting point. It can be calculated as follows :

x=\sqrt{1.5^2+0.8^2} \\\\x=1.7\ \text{miles}

Hence, he is 1.7 miles from his starting point.

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3 years ago
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