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viva [34]
3 years ago
8

Find two unit vectors orthogonal to a=⟨−2,−4,−2⟩a=⟨−2,−4,−2⟩ and b=⟨−3,5,2⟩b=⟨−3,5,2⟩ Enter your answer so that the first non-ze

ro coordinate of the first vector is positive. First Vector: ⟨⟨ , , ⟩⟩ Second Vector: ⟨⟨ , , ⟩⟩ Note: You can earn partial credit on this problem.
Mathematics
1 answer:
Levart [38]3 years ago
7 0

Answer:

u₁= ⟨1/(7*√3),−5/(7*√3) ,−11/(7*√3)⟩

u₂= ⟨-1/(7*√3),5/(7*√3) ,11/(7*√3)⟩

Step-by-step explanation:

for  a=⟨−2,−4,−2⟩ and b=⟨−3,5,2⟩

a vector orthogonal to a and b can be found through the vectorial product of a and b. Thus

c= a x bc=\left[\begin{array}{ccc}i&j&k\\-2&-4&-2\\-3&5&2\end{array}\right] =  \left[\begin{array}{ccc}-4&-2\\5&2\end{array}\right]*i+\left[\begin{array}{ccc}-2&-2\\-3&2\end{array}\right]*j+\left[\begin{array}{ccc}-2&-4\\-3&5\end{array}\right]*k = 2*i  -10*j  - 22*k

then c₁=⟨2,−10,−22⟩ and c₂= - c₁= ⟨-2,10,22⟩ are orthogonal to a and b

the corresponding unit vectors are

u₁=c₁/|c₁| = ⟨2,−10,−22⟩ / √(2²+(−10)²+(−22)²) = ⟨2,−10,−22⟩/(14*√3) =  ⟨1/(7*√3),−5/(7*√3) ,−11/(7*√3)⟩

then u₂= - u₁=  ⟨-1/(7*√3),5/(7*√3) ,11/(7*√3)⟩

then the unit vectors are

u₁= ⟨1/(7*√3),−5/(7*√3) ,−11/(7*√3)⟩

u₂= ⟨-1/(7*√3),5/(7*√3) ,11/(7*√3)⟩

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Answer:

$15

Step-by-step explanation:

Set up a proportion where x is the clearance price of the $40 shirt:

\frac{32}{12} = \frac{40}{x}

Cross multiply and solve for x:

32x = 480

x = 15

So, the clearance price is $15

8 0
3 years ago
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the length of a rectangle is 4a + 5, the width of the same rectangle is 2a -3 if the perimeter of the rectangle is 76 what is th
viktelen [127]

Answer:

Here

perimeter=76

length =4a+5

breadth=2a-3

we know,

perimeter=2(length+breadth)

76=2(4a+5+2a-3)

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76=14a+4

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7 0
2 years ago
A pet store sells goldfish and hermit crabs,
Elis [28]

Answer:

Cost = \$28

Step-by-step explanation:

Given

Represent Goldfish with g and hermit crabs with h.

The first statement, we have:

7g + 3h = 26

The second statement, we have:

4g + 5h = 28

Required

Determine the selling price of 6 goldfish and 4 hermit crabs

The equations are:

7g + 3h = 26 --- (1)

4g + 5h = 28 --- (2)

Make g the subject in (2)

4g + 5h = 28

4g = 28 - 5h

Divide both sides by 4

g = \frac{1}{4}(28 - 5h)

Substitute \frac{1}{4}(28 - 5h) for g in (1)

7g + 3h = 26

7(\frac{1}{4}(28 - 5h)) + 3h = 26

\frac{7}{4}(28 - 5h) + 3h = 26

Multiply through by 4

4 * \frac{7}{4}(28 - 5h) + 4*3h = 26*4

7(28 - 5h) + 4*3h = 26*4

Open bracket

196 - 35h + 12h = 104

196 -23h = 104

Collect Like Terms

-23h = 104-196

-23h = -92

Make h the subject

h = \frac{-92}{-23}

h = \frac{92}{23}

h = 4

Substitute 4 for h in g = \frac{1}{4}(28 - 5h)

g = \frac{1}{4}(28 - 5*4)

g = \frac{1}{4}(28 - 20)

g = \frac{1}{4}(8)

g = 2

This implies that:

1 goldfish = $2

1 hermit crab = $4

The cost of 6 goldfish and 4 hermit crabs is:

Cost = 6g + 4h

Cost = 6*\$2 + 4*\$4

Cost = \$12 + \$16

Cost = \$28

5 0
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Answer:

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Step-by-step explanation:

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