Darrel bought three t-shirts seeing that 41-5=36/12=THREE
The 1905 was 3.0 inches while 2004 was 4.2 inches since they are 1.2 apart and they add up to 7.2
Answer:
∠1 = 50°
∠2 = ∠3 = 130°
Step-by-step explanation:
In an isosceles trapezoid, such as this one, the angles at either end of a base are congruent:
∠1 ≅ 50°
∠2 ≅ ∠3
The theorems applicable to transversals and parallel lines also apply to the sides joining the parallel bases. In particular, "consecutive interior angles are supplementary." That is, angles 1 and 2 are supplementary, for example.
∠2 = 180° -∠1 = 180° -50° = 130°
We already know angle 3 is congruent to this.
∠1 = 50°
∠2 = ∠3 = 130°
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<em>Additional comment</em>
It can be easier to see the congruence of the base angles if you remove the length of the shorter base from both bases. This collapses the figure to an isosceles triangle and makes it obvious that the base angles are congruent.
Alternatively, you can drop an altitude to the longer base from each end of the shorter base. That will create two congruent right triangles at either end of the figure. Those will have congruent corresponding angles.
Since you're given the total cost per year (12,000) you multiply it by 4 so that you get the total amount for the four years. e.g. (4 x 12,000) = 480,000
Now you calculate the 75% from this amount because we want to obtain the amount of money the scholarship is worth. That is 480,000 x 75% = 360,000
or 480,000 x 0.75 = 360,000
So, the scholarship is of 360,000
There are a couple of different ways you could do this, but I'll show the simpler way. We will use the formula
along with the fact that the vertex has h and k coordinates of 1 and 4 respectively, and that a point on the graph is (3, 5). We could have used any point on the graph where there is a definite integer coordinate pair. We will fill in accordingly and solve for a.
and
5 = 4a + 4. If we subtract 4 from both sides we get that 
. Now we will fill in the formula and expand as needed:
and
. If we distribute the 1/4 in and then add the constants the final equation for that graph will be
