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Rainbow [258]
3 years ago
7

When the maximum value in a data set is exchanged for a higher

Mathematics
1 answer:
Kruka [31]3 years ago
5 0

Answer:

It doesn't change any of the other numbers of the five number summary. Only the maximum value of the data set changes, out of the five number summary of the data set.

Step-by-step explanation:

The five number summary of any data set consists of five values which includes

- The maximum value of the data set.

- The minimum values.

- The lower quartile.

- The upper quartile.

- The median.

These values are usually presented together and ordered from lowest to highest: minimum value, lower quartile (Q1), median value (Q2), upper quartile (Q3), maximum value.

Replacing the maximum value with a higher number doesn't change any of the other five number summary as they all position markers, whose values do not change because of changes at one end of the distribution as the positions of the other variables n the dataset are untouched.

This means that, of the five number summary, only the maximum value of the data set changes.

Although, values like the range, mean and standard deviation also change too.

Hope this Helps!!!

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A taxi driver charges a $2 fee plus an additional $4 per mile as shown by the graph.
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Answer:

The answer is 14

Step-by-step explanation:

The taxi driver charges $4 per mile so you multiply that by 3 miles because that is what your trying to find. So you get 12 and from their you have to add the $2 fee thus leading to an answer of 14.

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The length of a shadow of a tree is 150 feet when the angle of elevation of the sun is 39°. Approximate the height of the tree.
fomenos

Answer:

The height of tree is approximately 121.5 feet.

Step-by-step explanation:

We are given following in question:

Length of shadow = 150 feet

Angle of elevation of the sun =

\theta = 39^\circ

The tree and the shadow forms a right angled triangle.

Thus, with the help of trigonometric relation, we can write:

\tan \theta = \dfrac{\text{Height of tree}}{\text{Length of shadow}}

Let x feet be the height of tree.

Putting all the values, we get,

\tan 39^\circ = \dfrac{x}{150}\\\\0.80978 = \dfrac{x}{150}\\\\\Rightarrow x = 150\times 0.80978\\\Rightarrow x = 121.467 \approx 121.5

Thus, the height of tree is approximately 121.5 feet.

6 0
4 years ago
Find the area and perimeter of the compound figure below. (6 points)
fenix001 [56]

Answer:

  • area: 27.8 square units
  • perimeter: 21.2 units

Step-by-step explanation:

The area of a compound figure is the sum of the areas of its parts. The perimeter is the sum of the lengths of all of the edges.

<h3>Area</h3>

This compound figure is conveniently divided into a semicircle of radius 2.5 and a trapezoid with bases 5 and 7, and height 3.

<u>Semicircle</u>

The area of the semicircle is half the area of a circle with the same radius. It will be ...

  A = 1/2πr²

  A = 1/2π(2.5²) = 3.125π . . . . square units

<u>Trapezoid</u>

The area of the trapezoid is given by the formula ...

  A = 1/2(b1 +b2)h

  A = (1/2)(5 +7)(3) = 18 . . . . square units

Then the total area of the figure is ...

  3.125π +18 ≈ 27.8 . . . . square units

__

Perimeter

The perimeter will be the sum of the lengths of the straight line segments and the length of the semicircular arc.

<u>Arc</u>

  The arc length is half the circumference of the circle, so is ...

  arc = 1/2(2πr) = πr = 2.5π . . . . units

<u>Diagonal segments</u>

The figure is bounded by two congruent line segments that are each the hypotenuse of a triangle 1 unit wide and 3 units high. The Pythagorean theorem tells us that length is ...

  diagonal length = √(1² +3²) = √10 . . . . units

The two diagonal sides have a total length of 2√10 units.

<u>Horizontal segments</u>

The figure is bounded by two congruent horizontal segments of length 1 unit each, and one horizontal segment of length 5 units. Their total length is ...

  horizontal length = 1 + 1 + 5 = 7 . . . . units

The total perimeter is ...

  perimeter = horizontal length + diagonal length + arc length

  7 +2√10 +2.5π ≈ 21.2 . . . . units

7 0
3 years ago
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