Answer: 21%
Explanation: Let the radius of the circle =R therefore area of the circle = [pi][R * R]
Radius of the circle after 10% increase =R+10% of R=R+R/10=11R/10
Therefore AREA of the circle with radius 11R/10 =[pi][11R/10*11R/10]=[pi][121R*R/100] Hence INCREASE in the AREA of the circle=[pi][121R*R/100]-[pi][R*R] =[pi] [R*R][121/100-1] =[pi][R*R][121-100]/100=[pi][R*R][21]/100 THEREFORE % increase in the area of the circle=[pi][R*R][21/100]/[pi][R*R] whole multiplied by 100=21 HENCE increase in the area of the circle =21% NOTE : pi is a constant whose value=22/7
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The correct answer is 4... This is the correct exact answer
Answer:
The outer circle is 16 feet larger than the inner circle (68 - 52).
Step-by-step explanation:
Given that the inner circle circumference is 52 feet, and the distance between the inner and the outer circle is 8 feet, to determine by how many ft is the larger outer circle, the following calculation must be performed:
The radius of a circle is equal to half its diameter. Therefore, the radius of the inner circle is 26 feet. Thus, if the distance between the two circles is 8 feet, the radius of the outer circle is 34 feet (26 + 8). Therefore, the diameter of this circle is 68 feet (34 x 2).
This implies that the outer circle is 16 feet larger than the inner circle (68 - 52).
Answer:
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Step-by-step explanation:
The tangent of the angle is
... tan(α) = ay/ax = -8.6/6.1
Then the angle (measured CCW from +x) is
... α = arctan(-86/61) ≈ 305°
