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valentina_108 [34]
3 years ago
7

What is the least number of boxes needed to package 300 candies if each box will hold 16 candies?

Mathematics
1 answer:
maxonik [38]3 years ago
4 0
16 goes into 300,18.75 times but,we need the minimum number and since you can't cut a box into four quarter you would need a minimum of 19 boxes to package all of them.
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I’m failing this class and I need a lot of help! It would Be greatly appreciated!
olga55 [171]
I am pretty sure the answere is 4
5 0
3 years ago
Need help. <br><br> Enter an inequality that represents the graph in the box.
xxMikexx [17]
First you need to form a worthy equation using slope-intercept (y=mx+b). Do that by counting the slope and finding the y-intercept. Then you have to choose between < or > to make it more accurate. In order to do so, you would have to pick a point with a point x and y and see wether or not I’m the equation is true when you put it in the blanks. If it’s true then you would shade whichever region the point is. If it’s false then shade the opposite region.

Good luck!!!!!!! :)
5 0
3 years ago
6.
lys-0071 [83]

First, you have to divide the candles by 5.

225/5 = 45

That's it, so you get your answer 45!!!!

7 0
3 years ago
What's the simplest form of 72/75
Kruka [31]
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8 0
4 years ago
What are the coefficients for the expression <br><img src="https://tex.z-dn.net/?f=4x4%20%2B%20x3%20%20-%202x2%20-%206x%20%2B%20
kirill115 [55]
4x^4+x3-2x^2-6x+2
step by step:

(1): "x2" was replaced by "x^2". 2 more similar replacement(s).

2. ((((4•(x4))+(x3))-2x2)-6x)+2 (equation at the end of step 1)

3. equation at the end of step 2:

(((22x4 + x3) - 2x2) - 6x) + 2

4. polynomial roots caclulator:
3.1 Find roots (zeroes) of : F(x) = 4x4+x3-2x2-6x+2
Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient

In this case, the Leading Coefficient is 4 and the Trailing Constant is 2.

final result:

4x4 + x3 - 2x2 - 6x + 2
5 0
3 years ago
Read 2 more answers
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