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erastovalidia [21]
3 years ago
11

Sarah is cutting ribbons for a pep rally the length of each ribbon needs to be 3.72 inches if she needs 1,000 ribbons what is th

e length of ribbon Sarah needs?
Mathematics
1 answer:
HACTEHA [7]3 years ago
7 0

If she needs 1,000 ribbons at 3.72 inches each, She will need 1,000 x 3.72 which equals 3720 inches of ribbon.

This can be converted into feet by taking 3720 inches and dividing by 12 inches in a foot.

This will an answer of 310 feet.

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I never learned this. I tried I just don’t understand. Can anyone help
Scorpion4ik [409]

Answer:

Step-by-step explanation:

n = 25

33+n = 33+25 = 58

n/5 = 25/5 = 5

\sqrt{n+144}=\sqrt{25+144}=\sqrt{169}=13

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4 years ago
This is my question. If Andy drove 840 miles in 12 hours. How far could he drive in hours? Help me?
stellarik [79]

Answer:

840mi. - 12 hrs

  x       -  3 hrs

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840 _ 12

 x   --  3    ⇒12x=3(840) ⇒ 4x=280 ⇒ x=70 miles

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Step-by-step explanation:

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3 years ago
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3 years ago
A box contains 3 green marbles, 5 blue marbles, and 7 red marbles. Three marbles are selected at random from the box, one at a t
USPshnik [31]

Answer:

The probability is  P(K)  =   \frac{ 28 }{195}

Step-by-step explanation:

From the question we are told that

   The number of green marbles is  n_g  =  3

    The number of red marbles is  n_b  =  5

     The number of red marbles is  n_r  =  7

Generally the total number of marbles is mathematically represented as

       n_t  =  n_r  +  n_g + n_ b

        n_t  =  7 +  3 + 5

         n_t  = 5

Generally total number of marbles that are not red is  

     n_k  =  n_g +  n_ b

=>  n_k  =   3 +   5

=>  n_k  =  8

The probability of the first ball not being red is mathematically represented as  

      P(r') =  \frac{n_k}{n_t}

=>  P(r') =  \frac{ 8}{15}

The probability of the second ball not being red is mathematically represented as

      P(r'') =  \frac{n_k - 1}{n_t -1}

=>  P(r'') =  \frac{ 8 -1 }{15-1} (the subtraction is because the marbles where selected without replacement  )

=>  P(r'') =  \frac{ 7 }{14}

The probability that the first two balls  is  not red is mathematically represented as

    P(R) =  P(r') *  P(r'')

=>  P(R) =  \frac{ 8}{15} *   \frac{ 7 }{14}

=>  P(R) =  \frac{ 8 }{30}

The probability of the third ball being red is mathematically represented as

   P(r) =  \frac{n_r}{ n_t -2} (the subtraction is because the marbles where selected without replacement  )

     P(r) =  \frac{7}{ 15 -2}

=>    P(r) =  \frac{7}{ 13}

Generally the probability of the first two marble not being red and the third marble being red is mathematically represented as

        P(K)  =  P(R) * P(r)

         P(K)  =   \frac{ 8 }{30} * \frac{7}{ 13}

=>      P(K)  =   \frac{ 28 }{195}

6 0
3 years ago
6 × 2 − 4 × 5 + 12 ÷ 4 insert parentheses
Varvara68 [4.7K]

Answer: (6 x 2) - (4 x 5) + (12 / 4)

6 0
3 years ago
Read 2 more answers
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