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bagirrra123 [75]
3 years ago
10

="latex-formula">
Mathematics
2 answers:
olga55 [171]3 years ago
8 0
X=2

4(3x-2)=16
-> 3x-2=4 —> 3x=4+2 —> 3x+6 —> x=2
faust18 [17]3 years ago
7 0

Answer:

x=2

Step-by-step explanation:

12x-8=16

12x=24

x=2

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What is the probability the computer produces the first letter of your first name
inysia [295]

Answer:

1 out of 26

Step-by-step explanation:

Because there are 26 letters in the alphabet !

4 0
3 years ago
Divide. −1/9÷3/4 <br> −4/27 <br> −1/12 <br> 1/12 <br> 4/27<br> PLZZZZ HELP FAST!
ivanzaharov [21]

\frac{ - 1}{9}  \div  \frac{3}{4}  \\  \\  \frac{ - 1}{9}  \times  \frac{4}{3}  \\  \\  \frac{( - 1) \times 4}{9 \times 3}  \\  \\  \frac{ - 4}{27}

7 0
3 years ago
What is the volume in cubic units of a cylinder diameter 6 and height 4
katrin2010 [14]

Hey there!

The formula for the volume of a cylinder is \pi r^{2} h, which is essentially the base multiplied by the height.

If our diameter is six, then our radius is three, so we can solve for our base below. We will use 3.14 for pi.

3^{2}(3.14)=28.26

Now, we multiply this by our height of four.

28.26(4)=113.04

Therefore, our volume is 113.04 cubic units.

I hope this helps!

3 0
2 years ago
A line contains the two points plotted in the coordinate plane below.
Andrew [12]

Answer:

The slope would be 3.

Step-by-step explanation:

The formula for finding slope is \frac{y1-y2}{x1-x2}
We can plug these numbers into the equation by doing \frac{1--5}{2-0}
1--5 is equal to 1+5, which is 6.
2-0 is equal to 2.
\frac{6}{2} is 3, which is how you get your answer.
I hope this helps! :)

6 0
2 years ago
If dy/dx = x(y-1), find the equation of the tangent line at x=-2 with f(-2)=3
Lapatulllka [165]

Answer:

The equation of the tangent line passing through the point (-2,3) is

 4 x + y +5 =0

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given that the slope of the tangent</em>

<em>              </em>m = \frac{dy}{dx} = x(y-1)<em></em>

<em>              m = -2( 3-1) = -4</em>

<em>Given point x = -2</em>

<em>          y = f(-2) =3</em>

<em>∴The given point ( x₁ , y₁) = ( -2 ,3)</em>

<u><em>Step(ii):-</em></u>

The equation of the tangent line passing through the point (-2,3)

y - y_{1} = m(x-x_{1} )

y -3 = -4(x-(-2))

y -3 = -4( x+2)

y-3 = -4x -8

4x + y -3+8=0

4x +y +5=0

<u><em>Step(iii):-</em></u>

<em>The equation of the tangent line passing through the point (-2,3) is</em>

<em>   4 x + y +5 =0</em>

<em></em>

3 0
2 years ago
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