HELP !!

Mathematics

1 answer:

Snowcat [4.5K]3 years ago

6 0

The first set of eqatuions seems to be point slope form

y-y1=m(x-x1)
a point on the garph is (x1,y1) and the slope is m

ok, so slope=rise/run
in this case, frim (-2,3) to (3,0), the rise is -3 and run is 5 to slope is -3/5

a point is ehter (-2,3) or (3,0)

so the first equation is either y-0=-3/5(x-3) or y-3=-3/5(x+2)
that is the first option, y-0=-3/5(x-3)

the 2nd blank is solve for y
y-0=-3/5(x-3)
y=-3/5x+9/5
last one

so the first blank is y-0=-3/5(x-3) and the 2nd is y=-2/4x+9/5

You might be interested in

3m+4=1 with steps. THX

Fed [463]

3m+4=1
subtract 4 on both sides
3m=-3
divide both sides by 3
m=-1

4 0

3 years ago

A computer is used to generate passwords made up of numbers 0 through 9 and lowercase letters. The computer generates 400 passwo

tamaranim1 [39]

The prediction for the number of passwords in which the first character is a vowel is 56 passwords.

<h3>How to find that a given condition can be modelled by binomial distribution?</h3>

Binomial distributions consist of n independent Bernoulli trials.

Bernoulli trials are those trials which end up randomly either on success (with probability p) or on failures( with probability 1- p = q (say))

Suppose we have random variable X pertaining to a binomial distribution with parameters n and p, then it is written as

$X \sim B(n,p)$

The probability that out of n trials, there'd be x successes is given by

$P(X =x) = \: ^nC_xp^x(1-p)^{n-x}$

The expected value and variance of X are:

$E(X) = np\\$

Given that the characters that can be used are numbers 0 through 9 and lowercase letters. Therefore, a total of 36 different characters are available.

Since we need to know the passwords made with vowels, therefore, the probability of a password in which the first character will be a, e, i, o, u is (5/36).

Now as the computer produces 400 passwords, therefore, the predicted value can be written as,

$E = np = 400 \times \dfrac{5}{36} = 55.5556 \approx 56$