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1 year ago

Find the solution to the system of equations 2x + y = 3 and x - y = 3.

Mathematics

2 answers:

GrogVix [38]1 year ago

8 0

Ans (2,-1)

2(2)+(-1)=3
4+(-1)=3
3=3
and
2-(-1)=3
2+1=3
3=3

IRISSAK [1]1 year ago

6 0

Answer:

(2, - 1 )

Step-by-step explanation:

2x + y = 3 → (1)

x - y = 3 → (2)

adding the 2 equations term by term will eliminate y

3x + 0 = 6

3x = 6 ( divide both sides by 3 )

x = 2

substitute x = 2 into either of the 2 equations and solve for y

substituting into (1)

2(2) + y = 3

4 + y = 3 ( subtract 4 from both sides )

y = - 1

solution is (2, - 1 )

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Step 3: substitute x = 0 into the resulting function

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Step 4: Apply L'Hôpital's rule, by differentiating the numerator and denominator of the resulting function in step 2

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Step 7: substitute x = 0 into the resulting function in step 6

$= \dfrac{[ -cos(0)-2(sec^4(0)+2sec^2(0)tan^2(0)]}{6}\\\\= \dfrac{-1-2(0)}{6} \\= \dfrac{-1}{6}$

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