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Agata [3.3K]
2 years ago
8

A) Determine which amounts of postage can be formed using just 3-cent and 10-cent stamps.

Mathematics
1 answer:
RUDIKE [14]2 years ago
8 0

wait i will take screen shot please bran-list

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Help pleasseeeee ! 15 points<br><br> the answers are<br> (-1,-5)<br> (0,-3)<br> (4,5)<br> (9,15)
svet-max [94.6K]

Answer:

(0,-3)

Step-by-step explanation:

2x-y = 3

x+2y = -6

Multiply the first equation by 2 so we can eliminate y

2(2x-y =3)

4x -2y = 6

Add this to the second equation

4x -2y = 6

x+2y = -6

-----------------

5x +0y = 0

x = 0

Now find t

x+2y = -6

0+2y = -6

2y =-6

Divide by 2

y = -3

5 0
3 years ago
Read 2 more answers
(-4,-3) and (4,3) distance formula
TEA [102]

Answer:

The answer is 10

3 0
3 years ago
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Given the Arithmetic Sequence 9,12,15,18,21,...find the formula
Georgia [21]

Answer:

#1

__________________________________________________________

6 0
3 years ago
X²+7x+10=0 a=1, b=7, c=10 b²-4ac=(7)²-4(1) (10) =49-4(10) =49-40 =9​
Sloan [31]

Answer:

X=5

X=2

Step-by-step explanation:

8 0
3 years ago
During a scuba dive, Lainey descended to a point 19 feet below the ocean surface. She continued her descent at a rate of 25 feet
Leno4ka [110]

Answer:

25t+19\leq 144

t\leq5

The number of minutes she can continue to descend if she does not want to reach a point more than 144 feet below the ocean surface is <u>at most 5 minutes.</u>

Step-by-step explanation:

Given:

Initial depth of the scuba dive = 19 ft

Rate of descent = 25 ft/min

Maximum depth to be reached = 144 ft

Now, after 't' minutes, the depth reached by the scuba dive is equal to the sum of the initial depth and the depth covered in 't' minutes moving at the given rate.

Framing in equation form, we get:

Total depth = Initial Depth + Rate of descent × Time

Total depth = 19+25t

Now, as per question, the total depth should not be more than 144 feet. So,

\textrm{Total depth}\leq 144\ ft\\\\19+25t\leq 144\\\\or\ 25t+19\leq 144

Solving the above inequality for time 't', we get:

25t+19\leq 144\\\\25t\leq 144-19\\\\25t\leq 125\\\\t\leq \frac{125}{25}\\\\t\leq 5\ min

Therefore, the number of minutes she can continue to descend if she does not want to reach a point more than 144 feet below the ocean surface is at most 5 minutes.

7 0
3 years ago
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