Answer: 12in
Step-by-step explanation:
Length+width+length+width
To get the solution, we are looking for, we need to point out what we know.
1. We assume, that the number 45.5 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 45.5 is 100%, so we can write it down as 45.5=100%.
4. We know, that x is 6.81% of the output value, so we can write it down as x=6.81%.
5. Now we have two simple equations:
1) 45.5=100%
2) x=6.81%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
45.5/x=100%/6.81%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for what is 6.81% of 45.5
45.5/x=100/6.81
(45.5/x)*x=(100/6.81)*x - we multiply both sides of the equation by x
45.5=14.684287812041*x - we divide both sides of the equation by (14.684287812041) to get x
45.5/14.684287812041=x
3.09855=x
x=3.09855
now we have:
6.81% of 45.5=3.09855
Hope this helps!
3 sides of square is 3*12=36 cm
perimeter for the full circle is 2 * pi * radius
which is =2 * 22/7 * 12 =75.43 cm
so 360° =75.43 cm
for 150° = 75.43/360 *150 =31.43
all together =36 +31.43 =67.43 cm
Answer: 95% confidence interval for the difference between the proportions would be (1.31, 1.39).
Step-by-step explanation:
Since we have given that
Number of alluvial wells = 349
Number of quaternary wells = 143
Number of alluvial wells that had concentrations above 0.1 = 182
Number of quaternary wells that had concentrations above 0.1 = 112
Average of alluvial wells = 0.27
Standard deviation = 0.4
Average of quaternary wells = 1.62
Standard deviation =1.70
So, 95% confidence interval gives
alpha = 5% level of significance.

So, 95% confidence interval becomes,

Hence, 95% confidence interval for the difference between the proportions would be (1.31, 1.39).
Original position:
A-(-8,-4)
B-(-6,3)
C-(-3,7)
D-(-2,-2)
Translation:
A'-(-4,-4)
B'-(-2,3)
C'-(1,7)
D'-(2,-2)
Vertex C will be in quadrant 1 (+,+) after being translated 4 unites to the right.