Question

Who'd be better at speed answering? Datguy323 or some Helping Hand? (Not a serious question) Solve for the variables: https://tex.z-dn.net/?f=x%5E3%2By%5E7%3D28%5C%5Cx%5E3%3D27" id="TexFormula1" title="x^3+y^7=28\\x^3=27" alt="x^3+y^7=28\\x^3=27" align="absmiddle" class="latex-formula">

Answer 1

Answer: (3,1)

Step-by-step explanation:

First, to find x, simply take the cube root of 27, or 3.  Thus, x = 3.

Then, simply plug it in:

$27+y^7=28\\Subtract(27)\\y^7=1\\y=1$

Thus, y = 1

Hope it helps <3

p.s. for some reason, in a graphing calculator, it shows no solutions

Hope it helps <3

2 in a row!

Answer 2

Answer:

x = 3

y = 1

Step-by-step explanation:

The equations are:

$x^3+y^7 = 28$

and

$x^3 = 27$

Putting second equation in the first one:

=> $27+y^7 = 28$

Subtracting 27 to both sides

=> $y^7 = 28-27$

=> $y^7 = 1$

Taking power 7 to both sides

=> y = 1

Now,

$x^3 = 27$

Taking cube root on the both sides

x = 3