Let n represent the number.
.. (n -9)^2 = n -3 . . . . . the square of 9 less than the number is 3 less than the number
.. n^2 -18n +81 = n -3
.. n^2 -19n +84 = 0
.. (n -7)(n -12) = 0
.. n = 7 or 12
The number could be 7 or 12.
_____
Check:
.. (7 -9)^2 = (-2)^2 = 4 = 7 -3 . . . . answer checks OK
.. (12 -9)^2 = 3^2 = 9 = 12 -3 . . . . answer checks OK
I think graph 2. Hope this helps!
3.75
14.85
0.89
Those are the answers
<u>Given</u><u> info</u><u>:</u><u>-</u>
Aryan wants to plant a flower on the ground in the form of a rhombus.The diagonals of the rhombus measures 42 cm and 56 cm.
Find the perimeter of the field ?
<u>Explanation</u><u>:</u><u>-</u>
Given that
rhombus.The diagonals of the rhombus measures 42 cm and 56 cm.
Let consider a rhombus ABCD
Let AC = (d1) = 42 cm
Let BD = (d2) = 56 cm
We know that
The digonals of a rhombus bisects each other at 90°.
AC = AO+OC
⇛ AC = 2 AO = 2 OC
⇛ AO = OC = AC/2
⇛ AO = OC = 42/2 = 21 cm
and
BD = BO+OD
⇛ BD = 2 BO = 2 OD
⇛ BO = OD = BD/2
⇛ BO = OD = 56/2 = 28 cm
We have,
∆AOB is a right angled triangle
By Pythagoras theorem,
AB² = AO²+OB²
⇛ AB² = 21²+28²
⇛ AB² = 441+784
⇛ AB² = 1225
⇛ AB = ±√1225
⇛ AB = ±35
AB is the length of the side which cannot be negative.
AB = 35 cm
We know that
All sides are equal in a rhombus
⇛ AB = BC = CD = DA
As we know
The Perimeter of a rhombus = 4×Side units
The perimeter of the rhombus ABCD
⇛ 4AB = 4BC = 4CD = 4DA
⇛ 4×35 cm
⇛ Perimeter = 140 cm
<em>∴</em><em> </em><em>T</em><em>he perimeter of the given field is 140 cm.</em>
Answer: A. y= 5x(x-2)
Step-by-step explanation:
To begin with, this graph has two X values, making it a parabola
Parabola's are NOT linear.
