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Answer: Choice A) 0.20</h3>
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Explanation:
Let's say there are 1000 students. The students must take math, science or they can take both simultaneously.
- 65% of them are in math. So there are 0.65*1000 = 650 math students.
- 43% are in science, leading to 0.43*1000 = 430 science students.
- 13% are in both so we have 0.13*1000 = 130 students who are in both.
Now onto the sentence that says "Suppose a high school student who is enrolled in a math class is selected at random"
This means we only focus on the 650 math students and ignore the 1000-650 = 350 students who aren't in math.
Of those 650 math students, 130 are also in science (since 130 are in both classes).
The probability we're after is therefore 130/650 = 0.20
Step-by-step explanation:
Use PEMDAS
So the possible numbers are multiples of 6 smaller than 24:
6
12
18
24 is not ok, since he won both kinds of trophies, so if he won 24 soccer trophies, he'd have no baseball trophies!
if he had 12 of one kind of trophies, he'd have 24-12=12 also 12 of the other trophies, and we know that he has more soccer trophies, so we reject this
so he has 6 and 18 trophies of one kind. Since he has more soccer trophies, this means that he has 18 soccer trophies and 6 baseball trophies!
Answer:
x = $2.56
Step-by-step explanation:
To solve this, you do the inverse of both operations, which is multiplication and subtraction. The first inverse would be addition, so 2.81 + 2.31 = 5.12. Then, the second inverse would be division, so 5.12 divided by 2 = 2.56. So therefore, x = $2.56 is the correct answer for the price in September 2006.
Answer:
90
Step-by-step explanation:
Just multiply what the variables equal to
