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jekas [21]
3 years ago
10

A recent survey found that 65% of high school students were currently enrolled in a math class, 43% were currently enrolled in a

science class, and 13% were enrolled in both a math and a science class. Suppose a high school student who is enrolled in a math class is selected at random. What is the probability that the student is also enrolled in a science class?
0.20
0.28
0.30
0.66

Mathematics
2 answers:
fgiga [73]3 years ago
5 0
Two triangles are similar. Triangle ABC has side lengths of AB = 10, BC = 6, CA = 7. Triangle XYZ has a side length of XY = 8.
Bas_tet [7]3 years ago
4 0
<h3>Answer: Choice A)  0.20</h3>

===================================================

Explanation:

Let's say there are 1000 students. The students must take math, science or they can take both simultaneously.

  • 65% of them are in math. So there are 0.65*1000 = 650 math students.
  • 43% are in science, leading to 0.43*1000 = 430 science students.
  • 13% are in both so we have 0.13*1000 = 130 students who are in both.

Now onto the sentence that says "Suppose a high school student who is enrolled in a math class is selected at random"

This means we only focus on the 650 math students and ignore the 1000-650 = 350 students who aren't in math.

Of those 650 math students, 130 are also in science (since 130 are in both classes).

The probability we're after is therefore 130/650 = 0.20

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A local television station runs 2.5 minutes of commercials during every 30 minutes of programming. At this rate, how many minute
umka21 [38]

Answer:

12.5 minutes of commercials

Step-by-step explanation:

9:30 - 7:00 = 2 and a half hours on air = 150 minutes.

150 / 30 = 5

5 x 2.5 = 12.5

8 0
3 years ago
Read 2 more answers
From a group of 8 volunteers, including Andrew and Karen, 4 people are to be selected at random to organize a charity event. Wha
Helga [31]

Answer:

The correct option is D. 2/7

Step-by-step explanation:

Consider the provided information.

There are 8 volunteers including Andrew and Karen, 4 people are to be selected at random to organize a charity event.

We need to determine the probability Andrew will be among the 4 volunteers selected and Karen will not.

We want to select Andrew and 3 others but not Karen in the group.

Thus, the number of ways to select 3 member out of 8-2=6

(We subtract 2 from 8 because Andrew is already selected and we don't want Karen to be selected, so subtract 2 from 8.)

The required probability is:

\dfrac{^6C_3}{^8C_4}=\dfrac{\frac{6!}{3!3!}}{\frac{8!}{4!4!}}\\\\\\\dfrac{^6C_3}{^8C_4}=\frac{20}{70}\\\\\\\dfrac{^6C_3}{^8C_4}=\dfrac{2}{7}

Hence, the correct option is D. 2/7

6 0
3 years ago
What number should be added to both sides of the equation to complete the square? x2 8x = 4
Levart [38]
You would take half of the x term...and square it
so half of 8 is 4....4^2 = 16
u would add 16 to each side
6 0
3 years ago
Read 2 more answers
Divide quadratics by linear expressions (with remainders)
Anvisha [2.4K]

Answer:

x + 3 + \frac{13}{x-3}

Step-by-step explanation:

Divide using Synthetic division

dividing by ( x - 3)

Using 0 to represent the x- term

3 |  1  0   4

     ↓ 3    9

        +     +

   ------------------

     1   3    13 ← remainder

Thus

\frac{x^2+4}{x-3} = x + 3 + \frac{13}{x-3}

 

8 0
3 years ago
Round to the nearest ten thousand 1,346,935?
faltersainse [42]
First, find the number in the 10 thousands place. In 1,346,935, 4 is in the 10 thousands place. 6 is next to 4, and is larger than 5, so round 40 thousand to 50 thousand. The answer is 1,350,000.


Thanks for your question! Don't forget to rate and give me the brainliest answer! Then, I can help you with all your problems! ^-^ ~

7 0
3 years ago
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