Ask question

Ask question

All categories

4 years ago

15

A container holds 5L of fluid. Does it hold more than or less than 500mL of fluid

1 answer:

Yuri [45]4 years ago

7 0

There are 1000 mL in one liter, so there are 5000 Ml in the 5 L container. thus, it holds more than the 500 mL container.

You might be interested in

X =2y - 4 <br> x + 5y = -66<br> what is the x - value of the solution to this system of equation

stich3 [128]

Answer:x=-8 and y=-2

Step-by-step explanation:plug in for x.7(2y-4)+5y=6-6614y-28+5y=-6619y-28+-6619y=-38y=-2put it back in.

3 0

3 years ago

Gavyn was thinking of a number. Gavyn doubles it, then adds 14 to get an answer of 17.2. What was the original number?

VARVARA [1.3K]

Answer:

Original number we'll call "x".

2x + 14 = 17.2

x = 1.6

Step-by-step explanation:

6 0

3 years ago

A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece

Alex_Xolod [135]

Answer:

The number of seat when n is odd $S_n=\frac{n^2+2n+1}{4}$

The number of seat when n is even $S_n=\frac{n^2+2n}{4}$

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

$S_n=\frac{n}{2}[2a+(n-1)d]$

$=\frac{n}{2}[a+l]$

a = first term of the series.

d= common difference.

n= number of term

l= last term

$n^{th}$ term of a A.P series is

$T_n=a+(n-1)d$

n is odd:

n,n-2,n-4,........,5,3,1

Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=1 and d=2

$n=1+(t-1)2$

⇒(t-1)2=n-1

$\Rightarrow t-1=\frac{n-1}{2}$

$\Rightarrow t = \frac{n-1}{2}+1$

$\Rightarrow t = \frac{n-1+2}{2}$

$\Rightarrow t = \frac{n+1}{2}$

Last term l= n,, the number of term $=\frac{ n+1}2$ , First term = 1

Total number of seat

$S_n=\frac{\frac{n+1}{2}}{2}[1+n}]$

$=\frac{{n+1}}{4}[1+n}]$

$=\frac{(1+n)^2}{4}$

$=\frac{n^2+2n+1}{4}$

n is even:

n,n-2,n-4,.......,4,2

Or we can write

2,4,.......,n-4,n-2,n

Here a= 2 and d = second term- first term = 4-2=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=2 and d=2

$n=2+(t-1)2$

⇒(t-1)2=n-2

$\Rightarrow t-1=\frac{n-2}{2}$

$\Rightarrow t = \frac{n-2}{2}+1$

$\Rightarrow t = \frac{n-2+2}{2}$

$\Rightarrow t = \frac{n}{2}$

Last term l= n, the number of term $=\frac n2$ , First term = 2

Total number of seat

$S_n=\frac{\frac{n}{2}}{2}[2+n}]$

$=\frac{{n}}{4}[2+n}]$

$=\frac{n(2+n)}{4}$

$=\frac{n^2+2n}{4}$

4 0

3 years ago

What is the next term of the geometric sequence?<br> 3,15,75,

Contact [7]

Answer:

375

Step-by-step explanation:

3x5=15

15X5=75

75x5=375

8 0

3 years ago

Read 2 more answers

Help me find the answer for D and A please do it step by step for D and A

Vilka [71]

All triangles equal 180 degrees
92 + 50 = 142
180 - 142 = 38
Angle A equals 38 degrees

Angle 92 and Angle d Are supplementary which means that both angles added together equals 180
180-92 = 88
Angle d = 88 degrees

4 0

3 years ago