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Natali5045456 [20]
3 years ago
10

Pls help show work step by step

Mathematics
1 answer:
zhenek [66]3 years ago
6 0
The answer would be d=8t
This would be because the time they want is 1 hour. So when you plug in t as 1 you need d to equal 8. So you just have to change that 6 in the first equation to an 8. This new equation means that the person can travel 8 miles every hour.
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Please help me out on some questions...12th grade math..Pleasee help anyone​
gizmo_the_mogwai [7]

If all the angles of the triangle must equal 180, then we have to subtract the 2 known values from 180.

180 - 68.5 - 49.5 = x

62 = x

So that means the missing side is equal to 62!

⭐ Please consider brainliest! ⭐

✉️ If any further questions, inbox me! ✉️

6 0
3 years ago
9. Which of the following is the value of x in the solution to the
vladimir1956 [14]

Hi there,

9. Which of the following is the value of x in the solution to the

system of equations given below?

8 + 2x = 5y  (1)

4x - y = 2  (2)

▪ (1)

y = ( 8 + 2x ) ÷ 5

▪ (2)

4x - [( 8 + 2x ) ÷ 5] = 2

( 20x - 8 - 2x ) ÷ 5 = 2

20x - 8 - 2x = 2 × 5

20x - 2x = ( 2 × 5 ) + 8

18x = 10 + 8

18x = 18

x = 18 ÷ 18

x = 1

The answer is : A. 1

•It was nice to help you, SkullNoggin!

4 0
3 years ago
Warren owes $1,000 for a new laptop. He pays $100 each week.
lana [24]

Answer:

b) In 10 weeks, the loan is paid in full.

Step-by-step explanation:

10×$100=$1000

7 0
3 years ago
Read 2 more answers
Suppose you are given either a fair dice or an unfair dice (6-sided). You have no basis for considering either dice more likely
hoa [83]

Answer: Our required probability is 0.83.

Step-by-step explanation:

Since we have given that

Number of dices = 2

Number of fair dice = 1

Probability of getting a fair dice P(E₁) = \dfrac{1}{2}

Number of unfair dice = 1

Probability of getting a unfair dice  P(E₂) = \dfrac{1}{2}

Probability of getting a 3 for the fair dice P(A|E₁)= \dfrac{1}{6}

Probability of getting a 3 for the unfair dice P(A|E₂) = \dfrac{1}{3}

So, we need to find the probability that the die he rolled is fair given that the outcome is 3.

So, we will use "Bayes theorem":

P(E_1|A)=\dfrac{P(E_1)P(A|E_1)}{P(E_1)P(A|E_1)+P(E_2)P(A|E_2)}\\\\(E_1|A)=\dfrac{0.5\times 0.16}{0.5\times 0.16+0.5\times 0.34}\\\\P(E_1|A)=0.83

Hence, our required probability is 0.83.

8 0
3 years ago
) In 2005, the Health Department in Marion County, Indiana measured the heights and weights of 90,147 school-age children, allow
Lena [83]

Answer:

Since the calculated z=40  falls in the critical region this indicates that the true obesity rate for children in Marion County is different from the national average at the 0.05 significance level. We reject the null hypothesis that population proportion is 0.17.

Step-by-step explanation:

The national average is 17% .The z proportional hypothesis test is used.

1) Let the null and alternate hypothesis be

H0: p =0.17

against the claim

Ha: p ≠ 0.17

Choose the significance level ∝= 0.05

The critical region is z > 1.96  and Z <- 1.96 because  it is two tailed test.

Computing

z= p^-p / sqrt [pq/n]

Z= 0.22-0.17/ √0.17*(1- 0.17)/90147

z= 39.965

Since the calculated z=40  falls in the critical region this indicates that the true obesity rate for children in Marion County is different from the national average at the 0.05 significance level. We reject the null hypothesis that population proportion is 0.17.

3 0
3 years ago
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