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y = cos ^- 1 (x)
Step-by-step explanation:
The Function y = cos -1x = arccos x and its Graph: Since y = cos -1x is the inverse of the function y = cos x, the function y = cos -1x if and only if cos y = x. This leaves the range of the restricted function unchanged as [-1, 1].
The answer would be 2, 41° i think
The equidistant point for all three, will be the "centroid" of their triangular locations
thus
The slope is this and that