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3 years ago

Which of the following statements is true only if triangles EFI and GFH are similar?

Mathematics

2 answers:

s344n2d4d5 [400]3 years ago

7 0

Answer:

(some one already told the answer-)

Step-by-step explanation:

Two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion . In other words, similar triangles are the same shape, but not necessarily the same size.

The triangles are congruent if, in addition to this, their corresponding sides are of equal length.

Cerrena [4.2K]3 years ago

5 0

Answer:

Lines EI and HG are parallel

plz like and vote 5 star if answer is correct, if not still do it as it might help someone somehow

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4 years ago

A rectangular box has dimensions 2 in by 4 in by 4 in. Increasing each dimension of the box by the same amount yieits a new box

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3 years ago

When the crispy treats have cooled Mrs. Williams cut theme into 30 equal pieces and she give 2/5 to her son and takes the rest t

stiv31 [10]

Answer: Mrs, William takes 18 treats to school.

Step-by-step explanation:

Given: When the crispy treats have cooled Mrs. Williams cut theme into 30 equal pieces .

She give 2/5 to her son, then the number of treats ahe give to her son = $\frac{2}{5}30=12$

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Hence, Mrs, William takes 18 treats to school.

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3 years ago

What is the sum of the first 51 consecutive odd positive integers?

Angelina_Jolie [31]

We call:

$a_{n}$ as the set of the first 51 consecutive odd positive integers, so:

 $a_{n} = \{1, 3, 5, 7, 9...\}$

Where:
$a_{1} = 1$
$a_{2} = 3$
$a_{3} = 5$
$a_{4} = 7$
$a_{5} = 9$
and so on.

In mathematics, a sequence of numbers, such that the difference between two consecutive terms is constant, is called Arithmetic Progression, so:

3-1 = 2
5-3 = 2
7-5 = 2
9-7 = 2 and so on.

Then, the common difference is 2, thus:

 $a_{n} = \{ a_{1} , a_{1} + d, a_{1} + d + d,..., a_{1} + (n-2)d+d\}$

Then:

 $a_{n} = a_{1} + (n-1)d$

So, we need to find the sum of the members of the finite series, which is called arithmetic series:

There is a formula for arithmetic series, namely:

 $S_{k} = ( \frac{a_{1} + a_{k}}{2} ).k$

Therefore, we need to find:
 $a_{k} = a_{51}$

Given that $a_{1} = 1$ , then:

$a_{n} = a_{1} + (n-1)d = 1 + (n-1)(2) = 2n-1$

Thus:
$a_{k} = a_{51} = 2(51)-1 = 101$

Lastly:

$S_{51} = ( \frac{1 + 101}{2} ).51 = 2601$

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3 years ago