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kolezko [41]
3 years ago
5

Convert the polar representation of this complex number into its rectangular form: z=4(cos150°+ i sin150°) *the i before sin is

an imaginary number*
Mathematics
2 answers:
neonofarm [45]3 years ago
7 0

Answer:

z=2(-\sqrt{3}+i)

Step-by-step explanation:

The given polar representation of the complex number  is:

z=4(cos(150)^{\circ}+isin(150)^{\circ})

Thus, by solving the above equation, we have

⇒z=4(cos(90+60)+isin(90+60))

⇒z=4(-sin60^{\cic}+icos60^{\circ})

⇒z=4(\frac{\sqrt{3}}{2}+i\frac{1}{2}

⇒z=2(-\sqrt{3}+i)

which is the required rectangular form of the given polar complex number.

Charra [1.4K]3 years ago
6 0
Use z=a+bi=|z|(cos (theta)+i sin(theta)) to find the complex number solutions. z0=z0= -2sqrt3 + 2i
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