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kakasveta [241]
2 years ago
11

Maya spent her allowance on playing an arcade game a few times and riding the Ferris wheel more than once. Write about what addi

tional information you would need to create a two-variable equation for the scenario. What kind of problem could you solve with your equation?
Mathematics
1 answer:
Goryan [66]2 years ago
5 0

Answer:The information we need is how much money she had and how much she spent, also how much the games and Ferris wheel costs


Step-by-step explanation:


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Please help i’ll give brainliest
Ahat [919]

Answer:

Carla is correct

Step-by-step explanation:

When you multiple or divide a negative the sign changes, or flips the other side.

ex:-4x≥12

-4x/-4≥12/-4

x≤-3

hope this helps!

5 0
3 years ago
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How to make 8/11 into and improper fraction
kogti [31]
8/11 cant be an improper fraction because the numerator is smaller than the denominator
7 0
2 years ago
The price of a 32 pack of water at heb is $2.98. The tax rate is 8% what is the final cost of the water
SpyIntel [72]

Answer:

The final cost of the water is $3.22.

Step-by-step explanation:

In order to find the answer, you have to add the tax to the price of the 32 pack of water by calculating 8% of the price and adding that amount to it.

2.98*8%=0.24

2.98+0.24=3.22

According to this, the answer is that the final cost of the water is $3.22.

3 0
3 years ago
Your work<br> START<br> f(x)=2x² – 12x-5
MrMuchimi

Answer:

range = (− 23 ,  ∞ )

domain = ( − ∞ ,  ∞ )

y-intercept = -5

5 0
3 years ago
The velocity v and maximum height h of the water being pumped into the air are related by the equation v=\sqrt(2gh) where g is t
Whitepunk [10]

The velocity v and maximum height h of the water being pumped into the air are related by the equation

v= \sqrt{2gh}

where g = 32

(a) To find the equation that will give the maximum height of the water , solve the equation for h

v= \sqrt{2gh}

Take square root on both sides

v^2 = 2gh

Divide by 2g on both sides

\frac{v^2}{2g} = h

So maximum height of the water h = \frac{v^2}{2g}

(b) Maximum height h= 80

velocity v= 75 ft/sec

Given g = 32

h = \frac{v^2}{2g}

h = \frac{75^2}{2*32}

h= 87.89 ft

The pump withe the velocity of 75 ft/sec reaches the maximum height of 87.89 feet. 87.86 is greater than the maximum height 80 feet.

So the pump will meet the fire department needs.

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