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scoray [572]
3 years ago
15

What is the first derivative of 3\sqrt[3]{x^4}-12\sqrt[3]{x}?

Mathematics
1 answer:
Rainbow [258]3 years ago
8 0
\bf y=3\sqrt[3]{x^4}-12\sqrt[3]{x}\implies y=3x^{\frac{4}{3}}-12x^{\frac{1}{3}}
\\\\\\
\cfrac{dy}{dx}=3\left( \frac{4}{3}x^{\frac{1}{3}} \right)-12\left( \frac{1}{3}x^{-\frac{2}{3}} \right)\implies \cfrac{dy}{dx}=4x^{\frac{1}{3}}-4x^{-\frac{2}{3}}
\\\\\\
\cfrac{dy}{dx}=4\sqrt[3]{x}-\cfrac{4}{\sqrt[3]{x^2}}
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Answer:

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Step-by-step explanation:

To answer the question, we test each option as follows

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B. If p and q are distinct primes, then p2q2 has exactly 11 positive divisors.

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C. If p and q are distinct primes, then p+q is prime as well.

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D. If a divides b and c divides d, then a+c divides b+d.

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9 is divisible by 3

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E. If p is prime, then so is p+2.

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The above statement is true as both a and b are factors of c

H. There are infinitely many prime numbers.

The above statement is true as there are infinitely many numbers

I. If p is prime, then p2 has exactly 3 positive divisors.

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