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natulia [17]
4 years ago
8

HELP ASAP

Mathematics
2 answers:
Debora [2.8K]4 years ago
4 0
Just multiply 14 3/7 by 6 to get your answer.
Alik [6]4 years ago
3 0
Multiply 14 over 7 to get the number as one fraction. after adding three to that product, you get 101/7. Multiply that by 6/1 to get 606/7, then divide 606 by 7 to get 86 4/7 hours every 6 months.
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How do you calculate <br>√25+√16-√49 in BODMAS​
babymother [125]
<h2>Answer:</h2><h2>2</h2>

<h2>Solution: </h2>

\sqrt{25}  = 5 \\  \sqrt{16 }  = 4  \\  \sqrt{49}  = 7

5+4-7 = 9-7 = 2

Our Answer 2

<h2> </h2>

3 0
3 years ago
Read 2 more answers
There are 5 different coloured cups in a row.
Marizza181 [45]

There are 12 possible arrangements.

------------------------

  • Considering that the blue cup has to be on one end, we consider the number of arrangements possible with the other 4 cups, then multiply by 2(considering the blue on each end).

------------------------

  • Considering green and yellow before red and purple, there are 2 \times 2 = 4 outcomes(G-Y-R-P, G-Y-P-R, Y-G-R-P and Y-G-P-R).
  • Another two possible outcomes are yellow-purple and green-red, or vice-versa, thus 4 + 2 = 6 outcomes.
  • To account for the blue on the end, multiplying by 2. 2 \times 6 = 12
  • There are 12 possible arrangements.

A similar problem is given at brainly.com/question/24617788

6 0
3 years ago
What is $6.72divided by 3?
lara31 [8.8K]
It would be, 6.72/3 = $2.24
8 0
3 years ago
a father is now 38 years older than his son. Ten years ago he was twice as old as his son. let x represent the age of the son no
Helga [31]

The present age of father is 86 years old and present age of son is 48 years old

<em><u>Solution:</u></em>

Given that, a father is now 38 years older than his son

Ten years ago he was twice as old as his son

Let "x" be the age of son now

Therefore, from given,

Father age now = 38 + age of son now

Father age now = 38 + x

<em><u>Ten years ago he was twice as old as his son</u></em>

Age of son ten years ago = age of son now - 10

Age of son ten years ago = x - 10

Age of father ten years ago = 38 + x - 10

Then we get,

Age of father ten years ago = twice the age of son ten years ago

38 + x - 10 = 2(x - 10)

28 + x = 2x - 20

2x - x = 28 + 20

x = 48

Thus son age now is 48 years old

Father age now = x + 38 = 48 + 38 = 86

Thus present age of father is 86 years old and present age of son is 48 years old

7 0
4 years ago
*will give brainliest*
emmasim [6.3K]

Answer:

Y = 6 and x=6 are perpendicular because they both measure at a 90 degree angle

7 0
3 years ago
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