Answer:
0.665
Step-by-step explanation:
Given: 100 people are split into two groups 70 and 30. I group is given cough syrup treatment but second group did not.
Prob for a person to be in the cough medication group = 0.70
Out of people who received medication, 34% did not have cough
Prob for a person to be in cough medication and did not have cough
=
Prob for a person to be not in cough medication and did not have cough
=
Probability for a person not to have cough
= P(M1C')+P(M2C')
where M1 = event of having medication and M2 = not having medication and C' not having cough
This is because M1 and M2 are mutually exclusive and exhaustive
SO P(C') = 0.397+0.2=0.597
Hence required prob =P(M1/C') = 
Step-by-step explanation:
Y=1/3-3/1
-x+1= 1/3-3/1
= -3+1
= -2.
Answer: 6x+3y
Step-by-step explanation:
3x+3(x+y)= 3x+3x+3y=6x+3y
Answer:
2.1392938e+25Step-by-step explanation: you just times it so u get this answer