Answer:
A). 15
B). -1.2
Step-by-step explanation:
A). [10(x+3)]-20 = 160
10x+30-20 = 160
10x+10 = 160
10x = 160-10
10x = 150
x = 150/10
x = 15
B). 5{[4(8+(5x))]-9} = 85
5(32+20x+9) = 85
5(32+9+20x) = 85
5(41+20x) = 85
205+100x = 85
100x = 85-205
100x = -120
100x/100 = -120/100
x = -1.2
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HOPE THIS HELPS!!!
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I thought this would be easy lol, I tried, sorry for not getting an answer
It’s rather half of that or double of that
The answer should be A and D
the Highest common factor of 130,260,390 = 130
130 = 2⋅5⋅13
260 = 2⋅2⋅5⋅13
390 = 2⋅3⋅5⋅13
Common multipliers (130; 260; 390): 2, 5, 13
Now to find the highest Common factor you need to multiply the common factors
Answer: (130 ; 260 ; 390) = 2 ∙ 5 ∙ 13 = 130