Question

In circle O, AP = √10, PB = x and BC = 3. Find the value of x.

Answer 1

Answer:

The value of x is $2\ units$

Step-by-step explanation:

we know that

Applying the  tangent-secant theorem

$AP^{2}=PB*PC$

substitute the values and solve for x

$\sqrt{10}^{2}=x*(x+3)$

$10=x^{2}+3x$

$x^{2}+3x-10=0$

using a graphing tool

to solve the quadratic equation

The solution is $x=2\ units$

see the attached figure