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3 years ago

11

Which methods could you use to calculate the y-coordinate of the midpoint of vertical line segment with endpoints at (0,0) and (

0,15)? Check all that apply

1 answer:

Hatshy [7]3 years ago

5 0

Answer:

Midpoint formula.

The midpoint formula is (x_1+x_2)/2 , (y_1+y_2)/2

Step-by-step explanation:

This is one method. A list wasn't provided.

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Can someone help pleaseee its due soon

ahrayia [7]

Answer:is a rectangle

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The probability distribution for a random variable x is given in the table X: -5,-3,-2,0,2,3 Probability: .17,.13,.33,.16,.11,.1

Ivan

Answer:

0.6 probability that $-2 \leq x \leq 2$

Step-by-step explanation:

The probability distribution is given in the table.

Probability that x is between -2 and 2.

Between -2 and 2, inclusive, we have -2, 0 and 2. So

$P(-2 \leq x \leq 2) = P(X = -2) + P(X = 0) + P(X = 2)$

From the table:

$P(X = -2) = 0.33, P(X = 0) = 0.16, P(X = 2) = 0.11$ . So

$P(-2 \leq x \leq 2) = P(X = -2) + P(X = 0) + P(X = 2) = 0.33 + 0.16 + 0.11 = 0.60$

0.6 probability that $-2 \leq x \leq 2$

4 0

3 years ago

Calculate the total area of the shaded region.

LUCKY_DIMON [66]

so hmmm seemingly the graphs meet at -2 and +2 and 0, let's check

$\stackrel{f(x)}{2x^3-x^2-5x}~~ = ~~\stackrel{g(x)}{-x^2+3x}\implies 2x^3-5x=3x\implies 2x^3-8x=0 \\\\\\ 2x(x^2-4)=0\implies x^2=4\implies x=\pm\sqrt{4}\implies x= \begin{cases} 0\\ \pm 2 \end{cases}$

so f(x) = g(x) at those points, so let's take the integral of the top - bottom functions for both intervals, namely f(x) - g(x) from -2 to 0 and g(x) - f(x) from 0 to +2.

$\stackrel{f(x)}{2x^3-x^2-5x}~~ - ~~[\stackrel{g(x)}{-x^2+3x}]\implies 2x^3-x^2-5x+x^2-3x \\\\\\ 2x^3-8x\implies 2(x^3-4x)\implies \displaystyle 2\int\limits_{-2}^{0} (x^3-4x)dx \implies 2\left[ \cfrac{x^4}{4}-2x^2 \right]_{-2}^{0}\implies \boxed{8} \\\\[-0.35em] ~\dotfill$

$\stackrel{g(x)}{-x^2+3x}~~ - ~~[\stackrel{f(x)}{2x^3-x^2-5x}]\implies -x^2+3x-2x^3+x^2+5x \\\\\\ -2x^3+8x\implies 2(-x^3+4x) \\\\\\ \displaystyle 2\int\limits_{0}^{2} (-x^3+4x)dx \implies 2\left[ -\cfrac{x^4}{4}+2x^2 \right]_{0}^{2}\implies \boxed{8} ~\hfill \boxed{\stackrel{\textit{total area}}{8~~ + ~~8~~ = ~~16}}$

7 0

2 years ago

Help! You can look at the picture please

viva [34]

Answer:

$\frac{3x}{3 - 2x}$

Step-by-step explanation:

Here,

f(x) = y

$y = \frac{3x}{2x + 3}$

or , swapping x with y

$x = \frac{3y}{2y + 3}$

now to solve for y we get

$y = \frac{3x}{3 - 2x}$

now we put f inverse x instead of y

${f}^{ - 1} (x) = \frac{3x}{3 - 2x}$

I am done.

4 0

4 years ago

Read 2 more answers

The Great Pyramid has a height (h) of about 480 ft, a slant height (l) of about 560 ft and a square base of 756 ft. What is the

suter [353]

Answer: 91,445,760 ft³

Step-by-step explanation:

You know that the base of this pyramid is a square, then you can use the following formula to calculate its volume:

$V=\frac{s^2h}{3}$

Where "s" is the lenght of any side of the base of the pyramid and "h" is the height of the pyramid.

You know that:

$h=480ft\\s=756ft$

Then, you can substitute these values into the formula. So, you get that the volume of The Great Pyramid is:

$V=\frac{(756ft)^2(480ft)}{3}=91,445,760ft^3$

5 0

3 years ago