Answer:
2/9
Step-by-step explanation:
For the first draw:
We have,
Number of blue marbles (B)= 5
Total number of marbles (N)= 10
Probability of drawing a blue marble in first
draw [P(B)] = B/N
=5/10
=1/2
For the second draw when the initially drawn blue marble is not placed back in the bag:
We have,
Number of blue marbles (b) = 4
Total number of marbles (n) = 9
Probability of drawing a blue marble in the second draw [P(b)] = b/n
= 4/9
Finally,
Probability of drawing two blue marbles
[P(Bb)] = [P(B)] * [P(b)]
= 1/2 * 4/9
=2/9
Therefore, [P(Bb)] = 2/9
