Question

These marbles are placed in a bag and two

Answer 1

Answer:

2/9

Step-by-step explanation:

For the first draw:

We have,

Number of blue marbles (B)= 5

Total number of marbles (N)= 10

Probability of drawing a blue marble in first

draw [P(B)] = B/N

=5/10

=1/2

For the second draw when the initially drawn blue marble is not placed back in the bag:

We have,

Number of blue marbles (b) = 4

Total number of marbles (n) = 9

Probability of drawing a blue marble in the second draw [P(b)] = b/n

= 4/9

Finally,

Probability of drawing two blue marbles

[P(Bb)] = [P(B)] * [P(b)]

= 1/2 * 4/9

=2/9

Therefore, [P(Bb)] = 2/9