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fredd [130]
3 years ago
10

These marbles are placed in a bag and two

Mathematics
1 answer:
Anastaziya [24]3 years ago
8 0

Answer:

2/9

Step-by-step explanation:

For the first draw:

We have,

Number of blue marbles (B)= 5

Total number of marbles (N)= 10

Probability of drawing a blue marble in first

draw [P(B)] = B/N

=5/10

=1/2

For the second draw when the initially drawn blue marble is not placed back in the bag:

We have,

Number of blue marbles (b) = 4

Total number of marbles (n) = 9

Probability of drawing a blue marble in the second draw [P(b)] = b/n

= 4/9

Finally,

Probability of drawing two blue marbles

[P(Bb)] = [P(B)] * [P(b)]

= 1/2 * 4/9

=2/9

Therefore, [P(Bb)] = 2/9

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frozen [14]
First blank 4 —> (4,7)
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Third blank -2 —> (-2,4)
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Korvikt [17]

Answer:

The  UCL  is  UCL  =  0.054

The LCL  is  LCL \approx 0

Step-by-step explanation:

From the question we are told that  

     The quantity of each sample is  n =  30

     The  average of defective products is  p  =  0.025

Now  the upper control limit [UCL] is  mathematically represented as

       

      UCL  = p +  3 \sqrt{\frac{p(1-p)}{n}  }

substituting values  

      UCL  = 0.025 +  3 \sqrt{\frac{0.025 (1-0.025)}{30}  }

      UCL  =  0.054

The  upper control limit (LCL) is mathematically represented as

       LCL  = p -  3 \sqrt{\frac{p(1-p)}{n}  }

substituting values  

      LCL  = 0.025 -  3 \sqrt{\frac{0.025 (1-0.025)}{30}  }

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8 0
3 years ago
Mark for Review
ioda

Answer:

12 seconds

Step-by-step explanation:

Given

y = -2.5x + 30

Required

Determine the time taken to reach the ground

For the paper to reach the ground, y = 0

So, we have:

y = -2.5x + 30

0 = -2.5x + 30

Collect Like Terms

2.5x +0 = 30

2.5x = 30

Divide through by 2.5

2.5x/2.5 = 30/2.5

x = 30/2.5

x = 12

<em>Hence:</em>

<em>Time taken is 12 seconds</em>

5 0
4 years ago
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This leads to a perimeter of

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If you go around it twice, you'll run 800 meters

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4 years ago
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Answer: 5 + 25n

Explanation: Let's simplify this problem using the distributive property.

In this problem, the 5 "distributes" through the parentheses which means that it multiplies by each of the terms inside.

So we have 5(1) + 5(5n) which simplifies to 5 + 25n.

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