The 80 and 95 km/h speeds of cars A and B and their 5 and 2 m/s² acceleration gives the distance between them after 10 minutes as approximately 2,375.3 meters
<h3>What are the equations of the motion of the cars?</h3>
Top speed of car A = 80 km/h
Acceleration of car A = 5 m/s²
Top speed of car B = 95 km/h
Acceleration of car B = 2 m/s²
Time of travel = 10 minutes
The time, t1, it takes car A to reach the top speed is found as follows;
Where;
v = Final velocity (speed)
u = Initial velocity (speed)
a = Acceleration
t = Time
Whereby both cars start from rest, we have;
u = 0
v = 0 + a•t = a•t
Which gives;
The distance covered while accelerating is given by the formula;
s = u•t + 0.5•a•t²
Which gives;
The time of travel at top speed, t2, is given as follows;
Distance, s2 traveled at top speed is therefore;
The distance traveled by car A is therefore;
Similarly, for car B, we have;
The distance covered while accelerating is given by the formula;
The time of travel at top speed, t2, is given as follows;
Distance, s2 traveled at top speed is therefore;
The distance traveled by car B is therefore;
The distance between car A and car B in 10 minutes, is therefore;
The distance between car A and car B after 10 minutes is d ≈ <u>2375.3 m</u>.
Learn more about the equations of motion here:
brainly.com/question/10727726
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