We want to find the probability of getting a red ball in our first draw, given that in the second draw we got a white ball.
We will get P = 0.345
We know that the bowl has:
- 5 white balls
- 10 red balls
- 15 blue balls.
For a total of 30 balls.
We draw a ball and we store it.
Then we draw another ball and we see that it is a white ball.
We want to get the probability that the first ball was red.
The only thing we know, is that one of the white balls can be taken out of the sample space, because we can only draw it second if we did not draw it on the first attempt.
Then we can think that we have:
- 4 white balls.
- 10 red balls
- 15 blue balls.
For a total of 29 balls.
Then the probability of getting a red one is just the quotient between the number of red balls and the total number of balls, we will get:
P = 10/29 = 0.345
If you want to learn more, you can read:
brainly.com/question/11234923
Bro if i was you i’d just like do it 43
._ is the tenths place . Therefore the answer is 2.8
Answer:
g = h(e-10)
Step-by-step explanation:
You can multiply the whole equation by h to get g by itself.
