since the rate is a weekly basis, the period will also be in a weekly basis, so t = 4, assuming a month to be 4 weeks.
![~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$50\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ t=weeks\dotfill &4 \end{cases} \\\\\\ A=50[1+(0.05)(4)]\implies A=50(1.2)\implies A=60](https://tex.z-dn.net/?f=~~~~~~%20%5Ctextit%7BSimple%20Interest%20Earned%20Amount%7D%20%5C%5C%5C%5C%20A%3DP%281%2Brt%29%5Cqquad%20%5Cbegin%7Bcases%7D%20A%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%20P%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cdotfill%20%26%20%5C%2450%5C%5C%20r%3Drate%5Cto%205%5C%25%5Cto%20%5Cfrac%7B5%7D%7B100%7D%5Cdotfill%20%260.05%5C%5C%20t%3Dweeks%5Cdotfill%20%264%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20A%3D50%5B1%2B%280.05%29%284%29%5D%5Cimplies%20A%3D50%281.2%29%5Cimplies%20A%3D60)
You want to find the closest ten thousand that there is to 639,121.
So a ten thousand is basically anything that ends with four or more zeros.
For example:
530000 would be a ten thousand because it has four zeros at the end.
So you can see what the closest ten thousands are to 639,121 would be.
They would be:
630,000 and 640,000
Since they both have four zeros at the end.
Now you can just tell that 639,121 is closer to 640,000 because the digit in the thousands place, 9, is closer to 10 than 0.
Hope this helped :)
To add fractions you want to make sure that the bottom numbers are the same so we have to make them the same, but we have to make sure that the fractions are unchanged so we get the correct answer
so if we find out what number that 9,7, and 5 can all multiply into. we find that 9 times 7 times 5 or 315 is the number that will work
so to get them to all be over 315, we must multiply each fraction by a form of 1/1 or x/x or (number)/(same numbe as on top)
so 7/9 times (35/35)=245/315
1/7 times (45/45)=45/315
3/5 times (56/56)=168/315
we add them togther
245/315+45/315+168/315=(245+45+168)/315=458/315
this simplifies to 1 and 143/315
Answer:
A
Step-by-step explanation:
If two nonadjacent angles formed by two intersecting lines = Vertical angles= congruent
Then
Two non adjacent angles formed by two intersecting lines are congruent
