Question

Which system below has no solution?

Answer 1

Answer:

None of these options has "no solution"

Step-by-step explanation:

we will verify each options

(1)

y = 4x and y = 2x - 3

we can set them equal and solve for x

$4x=2x-3$

$2x=-3$

$x=-\frac{3}{2}$

Since, solutions exists

so, this is FALSE

(2)

y = -4x and y = 2x - 3

we can set them equal and solve for x

$-4x=2x-3$

$-6x=-3$

$x=\frac{1}{2}$

Since, solutions exists

so, this is FALSE

(3)

y = 4x and y = 2x+ 3

we can set them equal and solve for x

$4x=2x+3$

$2x=3$

$x=\frac{3}{2}$

Since, solutions exists

so, this is FALSE

(4)

y = -4-x and y = 2x - 3

we can set them equal and solve for x

$-4-x=2x-3$

$-3x=1$

$x=-\frac{1}{3}$

Since, solutions exists

so, this is FALSE

So, No system of equations have no solution