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3 years ago

What are the solutions to the quadratic equation 4x2 + 28x = 0?

Mathematics

2 answers:

IgorLugansk [536]3 years ago

7 0

4x^2+28x=0 factor out greatest common factor, 4x in this case

4x(x+7)=0

4x=0, x=0

x+7=0, x=-7

So x=0 and x=-7

devlian [24]3 years ago

5 0

X = 0 and x = -7 is your answer
Hope I helped < 3

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3 years ago

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Artyom0805 [142]

$\boxed{x=12 \ and \ x=2}$

<h2>Explanation:</h2>

In this exercise, we have the following equation:

$x^2-14x+49=25$

We can write this Quadratic Equation in Standard Form as follows:

$x^2-14x+49=25 \\ \\ Subtract \ 25 \ from \ both \ sides: \\ \\ x^2-14x+49-25=25-25 \\ \\ x^2-14x+24=0 \\ \\$

So this is a Non-perfect Square Trinomial. To factor out this, let's choose two numbers such that:

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Those numbers are:

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So we can write this as:

$x^2 + (a + b)x + ab=(x + a)(x + b) \\ \\ a=-12 \\ b=-2 \\ \\ x^2-14x+24=(x-12)(x-2)=0 \\ \\ So \ the \ solutions \ are: \\ \\ \boxed{x=12 \ and \ x=2}$

<h2>Learn more:</h2>

Quadratic Ffrmua: brainly.com/question/10188317

#LearnWithBrainly

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