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Ronch [10]
3 years ago
6

Which equation is true?

Mathematics
2 answers:
ch4aika [34]3 years ago
6 0

Answer : 9x^2 - 25 = (3x - 5)(3x + 5)

(1) 9x^2 - 25 = (3x - 5)(3x - 5)

Use FOIL method to mulitply (3x – 5)(3x – 5)

(3x - 5)(3x - 5)  = 9x^2 - 30x + 25

(2) 9x^2 - 25 = (3x - 5)(3x + 5)

Use FOIL method to mulitply (3x - 5)(3x + 5)

(3x - 5)(3x - 5)  = 9x^2 - 15x + 15x - 25 = 9x^2 - 25

(3) 9x^2 - 25 = -(3x + 5)(3x + 5)

Use FOIL method to mulitply -(3x + 5)(3x + 5)

-(3x + 5)(3x + 5)  = -(9x^2 + 30x + 25) = -9x^2 -30x -25

(4) 9x^2 - 25 = -(3x + 5)(3x - 5)

Use FOIL method to mulitply -(3x + 5)(3x - 5)

-(3x + 5)(3x - 5)  = -(9x^2 - 25) = -9x^2 + 25

So equation 2 is true

padilas [110]3 years ago
4 0
Hello,

Answer B


But this is not an equation!!!!! (only an expression)
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The bearing of the tree from Q is 296.565°

<h3>How to determine the height of the tree?</h3>

The figure that illustrates the bearing and the distance is added as an attachment

The given parameters are:

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Angle (x) = 32 degrees

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<h3>How to determine the distance between Q and the base of the tree?</h3>

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Hence, the distance between Q and the base of the tree is 111.80 meters

<h3>How to determine the angle of elevation?</h3>

The angle of elevation (x) using the following tangent trigonometric ratio

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<h3>The bearing of the tree from Q </h3>

This is calculated using:

Angle of bearing = 270 + arctan(50/100)

Evaluate the arc tan

Angle of bearing = 270 + 26.565

Evaluate the sum

Angle of bearing = 296.565

Hence, the bearing of the tree from Q is 296.565 degrees

Read more about bearings at:

brainly.com/question/24142612

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