3 years ago

PLEASE HELP, WILL MARK BRAINLIEST, 15 points

1 answer:

8 0

Step: 3 and 4

In step 3 you were suppose to add 34 to both sides to cancel it out which should have given you positive 17x=40

Im kinda confused if the problem is 2(10-13)=-34x+60 were did you get 9x and 26x on the left side

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EleoNora [17]

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$d(\frac{f(y)}{h(y)}) = \frac{f(y)*h'(y)-h(y)*f'(y)}{h^2(y)}$

Applying the quotient rule:

$g(y) = \frac{y-5}{y^2-3y+15}\\g'(y)=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}$

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3 years ago