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miskamm [114]
3 years ago
13

Find the illegal values of c in the multiplication statement c^2-3c-10/c^2+5c-14-c^2-c-2/c^2-2c-15

Mathematics
1 answer:
matrenka [14]3 years ago
3 0

<span>c^2 + 5c - 14 = 0 </span>
<span>(c-2)(c+7) = 0 </span>
<span>c-2 = 0 or c+7 = 0 </span>
<span>c = 2 or c = -7 </span>

<span>c^2 - 2c - 15 = 0 </span>
<span>(c-5)(c+3) = 0 </span>
<span>c-5 = 0 or c+3 = 0 </span>
<span>c = 5 or c = -3</span>
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6 0
3 years ago
Read 2 more answers
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Answer:

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Step-by-step explanation:

4 0
3 years ago
URGENT HELP<br> Solve for X
suter [353]

Answer:

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Step-by-step explanation:

95 + 85 + 100 + 27x -1 = 360

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Double check your work:

95 + 85 + 100 + 27(3) - 1 = 360

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7 0
2 years ago
If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen
Vlad [161]
The simultaneous equations are
2x - 7y = 4         (1)
3x + y = -17       (2)

Write (2) as
y = - 3x - 17       (3)

Substitute (3) into (1).
2x - 7(-3x - 17) = 4
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This is the equation obtained after substituting y from the second equation into the first equation.
The solution for y is
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Answer: x = -5

Note: The solution is x = -5,  y = -2.
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