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joja [24]
3 years ago
15

Two fraternities, Sig Ep and Ep Sig, plan to raise money jointly to benefit homeless people on Long Island. They will sell Yoda

vs. Alien T-shirts in the student center, but are not sure how much to charge. Sig Ep treasurer Augustus recalls that they once sold 240 shirts in a week at $5 per shirt, but Ep Sig treasurer Julius has solid research indicating that it is possible to sell 400 per week at $3 per shirt.
a. Based on this information, construct a linear demand equation for Yoda vs. Alien T-shirts, and hence obtain the weekly revenue R as a function of the unit price x.
b. The university administration charges the fraternities a weekly fee of $500 for use of the Student Center. Write down the monthly profit P as a function of the unit price x, and hence determine how much the fraternities should charge to obtain the largest possible weekly profit. What is the largest possible weekly profit?
Mathematics
1 answer:
WINSTONCH [101]3 years ago
7 0

Answer:

a. Based on this information, construct a linear demand equation for Yoda vs. Alien T-shirts, and hence obtain the weekly revenue R as a function of the unit price x.

  • y = 640 - 80x ⇒ demand equation
  • xy = - 80x² + 640x ⇒ weekly revenue

b. The university administration charges the fraternities a weekly fee of $500 for use of the Student Center. Write down the monthly profit P as a function of the unit price x, and hence determine how much the fraternities should charge to obtain the largest possible weekly profit. What is the largest possible weekly profit?

  • $780

Step-by-step explanation:

first, we must determine the slope = (400 - 240) / (3 - 5) = 160 / -2 = -80

the demand equation:

y - 240 = -80 (x - 5)

y = -80x + 400 + 240

y = 640 - 80x

total weekly revenue:

xy = -80x² + 640x

xy - 500 = -80x² + 640x - 500

max. profit ⇒ x = -640 / (2 x -80) = -640 / -160 = 4

maximum weekly profit = -80($4²) + 640($4) - $500 = -$1,280 + $2,560 - $500 = $780

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An urn contains nine red and one blue balls. A second urn contains one red and five blue balls. One ball is removed from each ur
il63 [147K]

Answer:

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Step-by-step explanation:

When drawing randomly from the 1st and 2nd urn, 4 case scenarios may happen:

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- Red ball is drawn from the 1st urn with a probability of 9/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (9/10)*(5/6) = 45/60 = 3/4 or 0.75. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 4 blue)/(8 red + 1 blue + 1 red + 4 blue) = 5/14

- Blue ball is drawn from the 1st urn with a probability of 1/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (1/10)*(5/6) = 5/60 = 1/12. The probability that a ball drawn randomly from the third urn is blue given this scenario is (4 blue)/(9 red + 1 red + 4 blue) = 4/14 = 2/7

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