The picture shows square JKLM and the dimension of rectangle RSTU.
2 answers:
<span>If the perimeters of these two quadrilaterals are equivalent, what is the length of</span>
RSTU=7+5+7+5 so the perimeter is 24.
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X² +4x+y²-2y=20(x+2)²+(y-1)²= 5² center (-2,1)
B cuz we *3*3*3 to reach to n 7
Sorry if i get this wrong... but I'd say 1/2
C. 48
