3 years ago

PLS HELP ME PLS!!!

Mathematics

1 answer:

Natasha2012 [34]3 years ago

8 0

Answer:

I don't know

Step-by-step explanation:

I (aee) - don't (dooont) - know (no)

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How do you rearrange the formula for the variable indicated:

PSYCHO15rus [73]

Watch closely. I'll try to go slow:

You said <u>v² = 2 g t</u>

Divide each side by 2g : <em>v² / 2g = t</em>

Did you follow that ?

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3 years ago

Find the limit of the function by using direct substitution.

musickatia [10]

Lim x->1 (x^2+8x-2)

substitute x =1
= 1^2 +8(1)-2
= 1 +8 -2
= 7

So the limit = 7

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3 years ago

Suppose temperature is at -6 what will the temperature be if it rises 13

Illusion [34]

7 degrees is what it would be

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3 years ago

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What are the X and Y intercepts of y= -2(x-4)2 +3

kari74 [83]

Answer: x-intercepts are ( 2.775,0) and (5.225,0)

And y-intercept is (0,-29)

Step-by-step explanation:

Here the given equation is,

$y = -2(x-4)^2+3$

For x-intercept, y = 0,

Put y = 0 in the above equation of parabola,

We get, $-2(x-4)^2 + 3 = 0$

$-2(x^2+16+8x) + 3 = 0$

$-2x^2-32-16x + 3 = 0$

$-2x^2-16x -29 = 0$

By solving this equation,

We get, x = 2.775 or x = 5.225

Therefore, x-intercept of the given parabola are (2.775, 0) and (5.225,0)

Now, for y-intercept, x = 0

By putting x = 0 in the given equation of parabola,

We get, y = -29

Thus, y-intercept of the given parabola = (0,-29)

4 0

3 years ago

Find the distance between the points with the given coordinates (-8,-6),(4,10)

Serggg [28]

Hello from MrBillDoesMath!

Answer:

Discussion:

Let (x1,y1) = (-8, -6) and (x2,y2) = (4,10). Per the distance formula,

Distance = sqrt ( (x1-x2)^2 + (y1-y2)^2 ) so

Distance = sqrt ( (-8-4)^2 + (-6-10)^2 )

= sqrt( (12)^2 + (-16)^2 )

= sqrt( 144 + 256 )

= sqrt(400)

= 20

Thank you,

MrB

3 0

3 years ago

Read 2 more answers