Yes it is. log(1) and ln(1) both equal zero. But you cannot take the logarithm of 0.
Answer:
The answer to the question are
(B) The set is not a vector space because it is not closed under addition. and
(D) The set is not a vector space because an additive inverse does not exist.
Step-by-step explanation:
To be able to identify the possible things that can affect a possible vector space one would have to practice on several exercises.
The vector space axioms that failed are as follows
(B) The set is not a vector space because it is not closed under addition.
(2·x⁸ + 3·x) + (-2·x⁸ +x) = 4·x which is not an eighth degree polynomial
(D) The set is not a vector space because an additive inverse does not exist.
There is no eight degree polynomial = 0
The axioms for real vector space are
- Addition: Possibility of forming the sum x+y which is in X from elements x and y which are also in X
- Inverse: Possibility of forming an inverse -x which is in X from an element x which is in X
- Scalar multiplication: The possibility of forming multiplication between an element x in X and a real number c of which the product cx is also an element of X
Simplify 6b2+7bc+2c2.
Hope this helps
