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Alex Ar [27]
3 years ago
5

The school is building a new pool with locker rooms. The locker rooms have the same area. What is the total area of the pool and

both locker rooms? A) 450 sq ft B) 460 sq ft C) 470 sq ft D) 480 sq ft

Mathematics
1 answer:
Rina8888 [55]3 years ago
8 0
<h3>Answer:</h3>

B) 460 sq ft

<h3>Explanation:</h3>

The area of a rectangle is computed as the product of length and width. The area of interest here can be decomposed into three rectangles:

... pool: 10 ft × 40 ft = 400 sq ft

... girls: 6 ft × 5 ft = 30 sq ft

... boys: same as girls, 30 sq ft.

Then the total area is the sum of these:

... total area = 400 sq ft + 30 sq ft + 30 sq ft = 460 sq ft

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Step-by-step explanation:

=9x+2(2x+3)

=9x+4x+6

=13x+6 I hope so,

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3 years ago
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In a circle of radius 10 cm, a sector has an area of 40 (pi) sq. cm. What is the degree measure of the arc of the sector?
Rashid [163]

Answer:

144°

Step-by-step explanation:

First, find the area of the circle, with the formula A = \pir²

Plug in 10 as the radius, and solve

A = \pir²

A = \pi(10²)

A = 100\pi

Using this, create a proportion that relates the area of the sector to the degree measure of the arc.

Let x represent the degree measure of the arc of the sector:

\frac{40\pi }{100\pi } = \frac{x}{360}

Cross multiply and solve for x:

100\pix = 14400\pi

x = 144

So, the degree measure of the sector arc is 144°

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3 years ago
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Select the polynomial that is a perfect square trinomial.
Alina [70]

Answer:

  16x^2 -8x +1

Step-by-step explanation:

The square of a binomial expands as ...

  (a +b)^2 = a^2 +2ab +b^2

So, you need to look for a trinomial with first and last terms that are perfect squares and a middle term that is double the product of the roots of those terms.

This pattern matches ...

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6 0
3 years ago
F(t) = -(t-2) (t-15)
Goryan [66]

Answer:

smaller (t) = 2 and this in coordinates form (2,0)

larger (t) = 15 and this in coordinates form (15,0)

the vertex of the parabola =  (\frac{17}{2} ,\frac{169}{4} ) or in decimals (8.5, 42.25)

Step-by-step explanation:

  • For the zeros of the function take each bracket and make it equal to zero.

SMALLER (t):

(t-2)=0

(add 2 for both sides)

t=2

LARGER (t):

(t-15)=0

(add 15 for both sides)

t=15

  • For the vertex of the parabola you do:

step1: expand the brackets:

f(t)=-(t-2)(t-15)

f(t)= -t^{2} +17t-30

step2: define a,b and c using the expression ax^{2} +bx+c :

a= -1 (the coefficient of t^{2} )

b= 17 (the coefficient of t)

c= -30 (the single number without a letter)

step3: sub the values in the formula -\frac{b}{2a} to find the x coordinate of the vertex :

-\frac{b}{2a}

= - \frac{17}{2*-1}

= \frac{17}{2} or in decimals 8.5

step4: sub the value of t (the x-coordinate) in equation f(t):

f(t)= -t^{2} +17t-30

f ( \frac{17}{2})  = - (\frac{17}{2} )^{2}+ 17× \frac{17}{2} - 30

= -\frac{289}{4} + \frac{289}{2} -30

=\frac{169}{4} or in decimals 42.25

(THIS IS A PICTURE OF THE GRAPH↓)

6 0
3 years ago
Please what’s the value of x
Wewaii [24]
The value of z is 20
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3 years ago
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