Complete Question
A newsletter publisher believes that above 41% of their readers own a personal computer. Is there sufficient evidence at the 0.10 level to substantiate the publisher's claim?
State the null and alternative hypotheses for the above scenario.
Answer:
The null hypothesis is 
The alternative hypothesis 
Step-by-step explanation:
From the question we are told that
The population proportion is 
The level of significance is 
The null hypothesis is 
The alternative hypothesis 
Step-by-step explanation:
11.3x-12 for x=5
=3(5)-12
=15-12
=3
12.45+15(n-1) for n=6
=45+15(6-1)
=45+15(5)
=45+75
=120
Go up 6, right 4, and flip the graph over the x-axis.
(4t² - 64) / (t^4) =
4t²:t^4 - 64:t^4 =
4t^-2 - 64:t^4 =
1/(4t²) - 64/t^4 =
mmc 4t² e t^4 = 4t^4
t²/4t^4 - 4*64/4t^4 =
(t² - 256)/(4t^4)
Answer is i think
<span>0.67 for you diana</span>