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Setler79 [48]
3 years ago
12

On the unit circle, where 0 less-than pi, when is tangent theta undefined?

Mathematics
1 answer:
topjm [15]3 years ago
4 0

Answer:

Step-by-step explanation:

Recall that on the unit circle, each point is represented as (\cos(\theta), \sin(\theta)) where 0\leq \theta \leq 2\pi. In this case, we are asked to take a loot at the interval 0 \leq \theta \leq \pi.

We will use the definition of tangent to solve the problem. REcall that

\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}

So, in this case, tangent is undefined whenever the denominator is zero. That is, when \cos(\theta)=0. Checking the unit circle with the interval 0 \leq \theta \leq \pi, this restriction corresponds to the upper half of the unit circle. In this case, the x component of each point is cosine. We are interested at the points where \cos(\theta)=0.

. This happens only at the point (0,1), which is associated with the value of \theta = \frac{\pi}{2}

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A cellphone service provider charges $5.00 per month and $0.20 per minute per call. If a customer's current bill is $55, how man
andreev551 [17]

Answer:

250 minutes

Step-by-step explanation:

Given,

Cell phone charges for a month = $ 5.00,

Additional charges per minute = $0.20,

Let the cell phone is used for x minutes for a month such that the total bill is $ 55,

⇒ Cell phone charge for the month + additional charges for x minutes = $ 55

⇒ 5.00 + 0.20x = 55

Subtracting 5 on both sides,

0.20x = 50

x = 250,

Hence, the cell phone is used for 250 minutes.

Third option is correct.

3 0
2 years ago
Which side of the equation 12.6v = 12 - 15.5v would you isolate the variable terms? Why?
lozanna [386]
The left side, because you only need to move one thing, and you don't need to subtract after that. (you can add, much more easier)

hope this helps
4 0
2 years ago
Help i dont understand this ;/ and ty
cestrela7 [59]
The vertex is the center point of the line or the axis of symmetry
So your answer should be (-2, -5)
8 0
2 years ago
Read 2 more answers
What is the measure of angle z in this figure?
VladimirAG [237]
The measure for angle z is 137°. Because angle 43° and angle z are equal to 180°. Which leads u to this equation.
z = 180 - 43
7 0
3 years ago
If QS bisects PQT, SQT=(8x- 25),PQT=(9x+34), and SQR=112, find each measure.
Goryan [66]

The values of the angles are; x = 12°, m∠PQS = 71°, m∠PQT = 142° and m∠TQR = 41°

<h3>What are the measure of the each angle?</h3>

The required angles; x, m∠PQS, m∠PQT, and m∠TQR

The given parameters are bisects ∠PQT

m∠SQT = (8·x - 25)°

m∠PQT = (9·x + 34)°

m∠SQR = 112°

We have;

m∠PQT = m∠SQT + m∠PQS (Angle addition postulate)

m∠SQT ≅ m∠PQS (Angles formed by angle bisector are congruent)

m∠SQT = m∠PQS  by Definition of congruency

m∠PQT = 2 × m∠SQT

Therefore;

(9·x + 34)° = 2 × (8·x - 25)° = (16·x - 50)°

Collecting like terms gives:

(34 + 50)° = 16·x - 9·x = 7·x

7·x = 84°

x = 84°/7 = 12°

x = 12°

m∠SQT = (8·x - 25)°

Therefore;

m∠SQT = (8 × 12 - 25)° = 71°

m∠SQT = 71°

m∠PQT = 2 × m∠SQT

∴ m∠PQT = 2 × 71° = 142°

m∠PQT = 142°

m∠PQS = m∠SQT (Angles formed by the same bisector )

∴ m∠PQS = m∠SQT = 71°

m∠PQS = 71°

m∠SQR = m∠SQT + m∠TQR (Angle addition postulate)

m∠SQT = 71°

∴  m∠SQR = 112° = 71° + m∠TQR

m∠TQR = 112° - 71° = 41°

m∠TQR = 41°

Learn more about angles here:

brainly.com/question/2882938

#SPJ1

4 0
1 year ago
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